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Leni [432]
3 years ago
7

What are some rational numbers

Mathematics
1 answer:
Radda [10]3 years ago
5 0

Answer: 1,2,3,4,5,6,7,8,9,

Step-by-step explanation: all numbers that can be expressed as the quotient or fraction

hope this helps please mark brainliest if it did

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Which statements are true about the polynomial function? f(x)=x3−x2−4x+4
luda_lava [24]
To determine which of the statement is/are true, we simply have to evaluate the given choices.

  a.   f(x) = 0 when x = -1

     f(x) = (-1)^3 - (-1)^2 - 4(-1) + 4
     f(x) = 6

  FALSE

   b. f(x) divided by x - 1 has a remainder of 0.

     f(x) = (1)^3 - (1)^2 - 4(1) + 4
     f(x) = 1 - 1 - 4 + 4 = 0

  TRUE.


   c. (x - 1) is a factor of f(x)

  Since, the division of f(x) by x - 1 gave an answer of zero this means that it is a factor. 

    TRUE.

   d. f(-1) = 0.

 In relation to letter a of this item, if we are to substitute -1 to x of the given equation, the answer is 6 instead of zero. 
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3 years ago
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Nimfa-mama [501]

Answer:

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Step-by-step explanation:

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3 years ago
Name the property of equality that the statement illustrates <br> If x = y, then y = x.
Dafna1 [17]

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Solve the following surd given below <br>(1-√5)÷(1+√5)​
Shkiper50 [21]

\dfrac{1-\sqrt 5}{1+\sqrt 5}\\\\\\=\dfrac{\left( 1- \sqrt 5\right)\left( 1- \sqrt 5\right)}{\left( 1+ \sqrt 5\right)\left( 1- \sqrt 5\right)}\\\\\\=\dfrac{\left( 1-\sqrt 5)^2}{1^2 - \left(\sqrt 5 \right)^2}\\\\\\=\dfrac{1+\left(\sqrt 5 \right)^2 -2 \sqrt 5\cdot 1}{1-5}\\\\\\=\dfrac{1+5-2\sqrt 5}{-4}\\\\\\=-\dfrac{6-2\sqrt 5}{4}\\\\\\=-\dfrac{2\left(3-\sqrt 5 \right)}{4}\\\\\\=-\dfrac{3-\sqrt 5}{ 2}\\\\\\=\dfrac{\sqrt 5 -3}{2}

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3 years ago
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alexira [117]

Answer:

19

Step-by-step explanation:

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