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3 years ago

Given: Line Segment AC ≅ Line Segment DC, ∠B≅∠D

Mathematics

1 answer:

Neporo4naja [7]3 years ago

7 0

Answer:

See Below.

Step-by-step explanation:

<u>Statements</u> <u>Reasons: </u>

<u /> $1)\text{ } AC\cong DC$ Given

$2)\text{ } \angle B\cong \angle D$ Given

$3)\angle BCA \cong \angle ECD$ Vertical Angles are Congruent

$4)\text{ } \Delta ACB\cong \Delta DCE$ AAS Congruence

$5)\text{ } AB\cong DE$ CPCTC

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<h2>Answer:</h2>

y = 2

<h2>Step-by-step explanation:</h2>

To determine the equation of the line that passes through (10,2) and (-3,2), we need to determine the slope of the line. Then substitute the slope and any given point in point slope form to obtain the equation of the line.

<h3>Finding the Slope of the line:</h3>

$\implies \text{Slope} = \dfrac{\text{Rise}}{\text{Run}} = \dfrac{y_{2} - y_{1} }{x_{2} - x_{1} }$

$\implies \text{Slope} = \dfrac{y_{2} - y_{1} }{x_{2} - x_{1} }$

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$\implies \text{Slope} = \dfrac{0}{-3 - 10 }$

∴ 0 divided by ANY number is ALWAYS 0.

$\implies \text{Slope} =0$

<h3>Finding the equation of the line:</h3>

Point slope form formula: y - y₁ = m(x - x₁)

x₁ and y₁ are the coordinates of any given point.
m is the slope

<u>Substitute the values in the point slope form:</u>

$\implies \text{Equation of line:} \ y - y_{1} = m(x - x_{1} )$

$\implies \text{Equation of line:} \ y - 2 = 0(x - 10)$

<u>Simplify the equation to determine the equation of the line:</u>

∴ Any number multiplied by 0 is 0.

$\implies \text{Equation of line:} \ y - 2 = 0$

$\implies \text{Equation of line:} \ y = 0 + 2$

$\implies \text{Equation of line:} \ y = 2$

Thus, the equation of the line is y = 2.

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