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3 years ago

Find the missing values in the ratio table.

Mathematics

1 answer:

netineya [11]3 years ago

3 0

Answer:

30:1:17

5:0.167:2.83

or 1 decimal place

30:1:17

5:0.2:2.8

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25 POINTS! Answer needed ASAP! You WILL be named Brainiest!

bija089 [108]

Answer:

We need to send more than 400 messages for Plan B to be the better option.

Step-by-step explanation:

Plan A

The cost is a flat fee of 30 plus 10 cents per message

Cost= 30 +.10m

Plan B

The cost is a flat fee of 50 plus 5 cents per message

Cost = 50 +.05m

We want cost of B to be less than cost A

30 +.10m > 50 +.05m

Subtract .05m from each side

30 +.10m- .05m > 50 +.05m-.05m

30 +.05m > 50

Subtract 30 from each side

30-30 +.05m > 50-30

.05m > 20

Divide each side by .05

.05/.05m > 20/.05

m > 400

We need to send more than 400 messages for Plan B to be the better option.

4 0

3 years ago

Find Y. Round to the nearest tenth. Z 17 ft 8 ft X 16 ft Y Y= [?]° Law of Cosines: c2 = a + b2 - 2ab cos C

ludmilkaskok [199]

Answer:

27.8

Step-by-step explanation:

6 0

2 years ago

HELP!!!

ella [17]

Answer:

120

Step-by-step explanation:

We are given that the function for the number of students enrolled in a new course is $f(x) = 4^{x}-1$ .

It is asked to find the average increase in the number of students enrolled per hour between 2 to 4 hours.

We know that the average rate of change is given by,

$A = \frac{f(x)-f(a)}{x-a}$ ,

where f(x)-f(a) is the change in the function as the input value (x-a) changes.

Now, the number of students enrolled at 4 = f(4) = $f(x) = 4^{4}-1$ = 255 and the number of students enrolled at 2 = f(2) = $f(x) = 4^{2}-1$ = 15

So, the average increase $A=\frac{f(4)-f(2)}{4-2}$ = $A=\frac{255-15}{4-2}$ = $A=\frac{240}{2}$ = 120.

Hence, the average increase in the number of students enrolled is 120.

3 0

3 years ago

The manager of a sporting goods store ordered 256 packages of football cards to be shipped to the store there are 24 cards in ea

Allisa [31]

He ordered 6144 football cards

7 0

3 years ago

Read 2 more answers

Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal plac

Serhud [2]

Answer:

Step-by-step explanation:

A) $(tanx-4)(9sin^2x-1)=0\\\\\\$

$9sin^2x-1=0\\\\sin^2x=\frac{1}{9} sinx=\frac{1}{3}$ or $sinx=\frac{-1}{3}$

OR $tanx=4\\$

$3sin2x=3.2.sinx.cosx\\\\6.sinx.cosx-4.sinx= 2sinx.(3cosx-2)=0\\\\3.cosx=2 cosx=\frac{2}{3}$

3 0

2 years ago