If 6 beads weigh 48 grams, how many beads weigh 72 grams?

Mathematics

2 answers:

allochka39001 [22]3 years ago

4 0

Nine.
48 divided by 6 is 8, which means that each bead weighs 8 grams.
72 divided by 8 is nine.

zalisa [80]3 years ago

3 0

Hey there!

To solve for the amount of beads that weigh 72 grams, you can set up this proportion where x represents the number of beads weighing 72 grams:
$\frac{6}{48}$ = $\frac{x}{72}$

Now, cross multiply and simplify:
6*72=48*x
432=48x

Finally, solve for x:
432=48x
x=9

Therefore, 9 beads will weigh 72 grams.

Hope this helps and I hope you have a marvelous day! :)

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Fudgin [204]

Answer:

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Step-by-step explanation:

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3 0

3 years ago

During the first stages of an epidemic, the number of sick people increases exponentially with time. Suppose that at = 0 days th

nydimaria [60]

T = days passed

r = rate of growth

by 0 day, or t = 0, there are 2 folks sick,

$\bf \qquad \textit{Amount for Exponential Growth}
\\\\
A=P(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &2\\
P=\textit{initial amount}\\
r=rate\to r\%\to \frac{r}{100}\\
t=\textit{elapsed time}\to &0\\
\end{cases}
\\\\\\
2=P(1+r)^0\implies 2=P\cdot 1\implies 2=P\qquad \boxed{A=2(1+r)^t}$

by the third day, t = 3, there are 40 folks sick,

$\bf \qquad \textit{Amount for Exponential Growth}
\\\\
A=P(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &40\\
P=\textit{initial amount}\to &2\\
r=rate\to r\%\to \frac{r}{100}\\
t=\textit{elapsed time}\to &3\\
\end{cases}
\\\\\\
40=2(1+r)^3\implies 20=(1+r)^3\implies \sqrt[3]{20}=1+r
\\\\\\
\sqrt[3]{20}-1=r\implies 1.7\approx r\qquad \boxed{A=2(2.7)^t}$

how many folks are there sick by t = 6? $\bf \stackrel{that~many}{A=2(2.7)^6}$