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Anika [276]
3 years ago
13

I WILL GIVE BRAINLIEST to who answers this question correctly.

Mathematics
1 answer:
Alborosie3 years ago
4 0
You start counting from 0 onwards:

C = 6
D = 8

Then C x D = 48

So the product CxD is situated at 48 units from 0



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DaJuan has a photo that is 4 inches in width by 6 inches in length that
goldenfox [79]

Answer:3x-x+2=4

Step-by-step explanation: source: (Too much work) srry

5 0
2 years ago
Suppose a deep sea diver dives from the surface to 202 feet below the surface. He then dives down 12 more feet. Use integers to
Elena L [17]

Answer:

B.) (-202)+(-12)

Step-by-step explanation:

The undersea level is negative then going under again will produce a completely negative answer.

6 0
2 years ago
Simplify your answer to the previous part and enter a differential equation in terms of the dependent variable xx satisfied by x
rusak2 [61]

Answer:

x'-5x=0, or x''-25x=0, or x'''-125x=0

Step-by-step explanation:

The function x(t)=e^{5t} is infinitely differentiable, so it satisfies a infinite number of differential equations. The required answer depends on your previous part, so I will describe a general procedure to obtain the equations.

Using rules of differentiation, we obtain that x'(t)=5e^{5t}=5x \text{ then }x'-5x=0. Differentiate again to obtain, x''(t)=25e^{5t}=25x=5x' \text{ then }x''-25x=0=x''-5x'. Repeating this process, x'''(t)=125e^{5t}=125x=25x' \text{ then }x'''-125x=0=x'''-25x'.

This can repeated infinitely, so it is possible to obtain a differential equation of order n. The key is to differentiate the required number of times and write the equation in terms of x.

7 0
2 years ago
Suppose that you toss a fair six-sided {1,2,3,4,5,6} die and let X represent the outcome obtained. Find the expected volume of a
timofeeve [1]

Answer:

The expected volume of the box is 364 cubic inches.

Step-by-step explanation:

Since the die is fair, then P(X=k) = 1/6 for any k in {1,2,3,4,5,6}. Let Y represent the volume of the box in cubic inches. For how the box is formed, Y = X²*24. Thus, the value of Y depends directly on the value of X, and we have

  • (When X = 1) Y = 1²*24 = 24, with probability 1/6 (the same than P(X=1)
  • (When X = 2) Y = 2²*24 = 96, with probability 1/6 (the same than P(X=2)
  • (When X = 3) Y = 3²*24 = 216, with probability 1/6 (the same than P(X=3)
  • (When X = 4) Y = 4²*24 = 384, with probability 1/6 (the same than P(X=4)
  • (When X = 5) Y = 5²*24 = 600, with probability 1/6 (the same than P(X=5)
  • (When X = 6) Y = 6²*24 = 864, with probability 1/6 (the same than P(X=6)

As a consequence, the expected volume of the box in cubic inches is

E(Y) = 1/6 * 24 + 1/6*96 + 1/6*216+ 1/6*384+ 1/6*600+1/6*864 = 364

3 0
3 years ago
Choose the equation that you can use to solve
dybincka [34]

Step-by-step explanation:

step 1. #1 has no x

step 2. #2 has infinite solutions

step 3. #4 has y but no x

step 4. x^2 - x = 6 can be solved for x.

7 0
3 years ago
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