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3 years ago

I WILL GIVE BRAINLIEST to who answers this question correctly.

Mathematics

1 answer:

Alborosie3 years ago

4 0

You start counting from 0 onwards:

C = 6
D = 8

Then C x D = 48

So the product CxD is situated at 48 units from 0

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Which two whole numbers does 7 1/2 lie between

goldfiish [28.3K]

Hi there! :)

Answer:

7 1/2 lies between the two whole numbers 7 and 8.

Step-by-step explanation:

"Whole numbers" are numbers without fractional or decimal parts and no negatives.

The first whole number BEFORE 7 1/2 is 7.

The first whole number AFTER 7 1/2 is 8.

There you go! I really hope this helped, if there's anything just let me know! :)

4 0

3 years ago

Read 2 more answers

Help me out please! i really need it

otez555 [7]

Answer:

x=14

Step-by-step explanation:

to find x you have to isolate it so you divide 3 by both sides and that leaves you with the answer

3 0

3 years ago

Read 2 more answers

Whats (-1) - (1/3) please hurry (in the form of a fraction)

prohojiy [21]

The answer is 2/3
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3 0

2 years ago

The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the

gladu [14]

Answer:

Part 1) Australia $19,751,012\ people$

Part 2) China $1,319,645,764\ people$

Part 3) Mexico $109,712,539\ people$

Part 4) Zaire $60,534,681\ people$

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$P(t)=a(1+r)^t$

where

P(t) is the population

t is the number of years since year 2000

a is he initial value

r is the rate of change

Part 1) Australia

we have

$a=19,169,000\\r=0.6\%=0.6\100=0.006$

substitute

$P(t)=19,169,000(1+0.006)^t$

$P(t)=19,169,000(1.006)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=19,169,000(1.006)^5=19,751,012\ people$

Part 2) China

we have

$a=1,261,832,000\\r=0.9\%=0.9\100=0.009$

substitute

$P(t)=1,261,832,000(1+0.009)^t$

$P(t)=1,261,832,000(1.009)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people$

Part 3) Mexico

we have

$a=100,350,000\\r=1.8\%=1.8\100=0.018$

substitute

$P(t)=100,350,000(1+0.018)^t$

$P(t)=100,350,000(1.018)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=100,350,000(1.018)^5=109,712,539\ people$

Part 4) Zaire

we have

$a=51,965,000\\r=3.1\%=3.1\100=0.031$

substitute

$P(t)=51,965,000(1+0.031)^t$

$P(t)=51,965,000(1.031)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=51,965,000(1.031)^5=60,534,681\ people$

8 0

3 years ago

One day I found a strange thing happening to my watch,the minute hand & the hour hand were coming together every 65 minutes.

brilliants [131]

Answer:

Step-by-step explanation:

The minute hand of a clock overtakes the hour hand at intervalsof M minutes of correct time. The clock gains or loses in a day by=(720/11−M)(60×24/M) minutes.

Here M = 64. The clock gains or losses in a day by

=(720/11−M)(60×24/M)=(720/11−64)(60×24/64)

=16/11(60×3/8)=2/11(60×3)=360/11=32(8/11) minutes.

5 0

3 years ago