Question

Heyy can you please help me posted picture of question

Answer 1

We can use quadratic formula to determine the roots of the given quadratic equation.

The quadratic formula is:

$x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a}$

b = coefficient of x term = 4
a = coefficient of squared term = 1
c = constant term = 7

Using the values, we get:

$x= \frac{-4+- \sqrt{16-4(1)(7)} }{2(1)} \\ \\ x= \frac{-4+- \sqrt{-12} }{2} \\ \\ x= \frac{-4+-2 \sqrt{-3} }{2} \\ \\ x= -2+- \sqrt{-3}$

So, the correct answer to this question is option A