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3 years ago

Three more than the product of two and a number x

Mathematics

2 answers:

AfilCa [17]3 years ago

5 0

The equation the statement shows is 2x+3

stepladder [879]3 years ago

5 0

The expression is 2x + 3.

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PLS HELP WILL MARK U BRAINLIEST!! NO FAKE ANSWERS

lana66690 [7]

Answer:

250,000

Step-by-step explanation:

4% of 250,000 is 10,000 so 15,000 + 10,000 = 25,000

6 0

2 years ago

Read 2 more answers

The slope of the line below is -2. Use the coordinates of the labeled point to

Vilka [71]

Answer:

We can express the equation for any linear equation with slope -2 and point (x0,y0) as:

$y=-2x+(y_0+2x_0)\\\\y-y_0=-2(x-x_0)$

Step-by-step explanation:

Incomplete question:

There is no point to complete the equation.

As we have no point to complete the linear equation, we will solve for any given point (x0,y0) and a slope of m=-2.

The linear equation can be written generically as:

$y(x)=mx+b\\\\y(x)=-2x+b$

If a point, like (x0,y0) belongs to the linear equation, it satisfies its equation. Then:

$y_0=-2x_0+b$

Then, we can calculate b as:

$y_0=-2x_0+b\\\\b=y_0+2x_0$

We can express the equation for any linear equation with slope -2 and point (x0,y0) as:

$y=-2x+(y_0+2x_0)\\\\y-y_0=-2(x-x_0)$

6 0

3 years ago

How many lines of symmetry does this regular polygon have A.0 B.1 C.2 D.5

REY [17]

Answer:

Step-by-step explanation:

the top pair and the middle pair

7 0

3 years ago

Read 2 more answers

A grasshopper jumps straight up from the ground with an initial vertical velocity of 8 feet per second. After how many seconds w

vlabodo [156]

Answer:

Problem 1 : After 0.25 s

Problem 2 : The squirrel doesn't reach the ground before the nut

Step-by-step explanation:

Problem 1

This is a standard physics problem

The equation that defines the movement of the grasshopper given the initial velocity, and the acceleration is the following

Distance = Do + Vo*t + 0.5*a*t^2

Where

Do is the initial distance.

(Do = 0, because the grasshopper is on the ground and we choose the reference system there)

Vo is the initial velocity = 8 feet/sec

a is the acceleration that is exerted on the body (in this case a = g = -9.8 m/s^2 = - 32.174 feet per second per second.)

t is the time

We substitute in the equation, and solve for t (time)

Distance = Do + Vo*t + 0.5*a*t^2

(1 foot)= (0)+ (8 feet/s)*t + 0.5*(-32.174 feet/s^2)*t^2

Solving this equation, we get that

t = 0.25 s

Problem 2

This problem is similar to the previous one

We apply the same formula

D = Do + Vo*t + 0.5*a*t^2

But in this case, we are going in the opposite direction, and we have an initial distance.

Do = 27 feet

Vo is the initial velocity of the nut = -6 feet/s

D = 0 (Ground)

We substitute in the equation, and solve for t (time)

(0) = (27) + (-6 feet/s)*t + 0.5*(-32 feet/s^2)*t^2

t = 1.125 s < 2s

The nut reaches ground in 1.125 s, so the squirrel doesn't reach the ground before the nut

4 0

3 years ago

20 POINTS PLEASE HELP

Andru [333]

The figure RQTS is a clockwise rotation of figure DEFC, then:
The image of CD is
Answer: Option C. RS

8 0

2 years ago