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GarryVolchara [31]
3 years ago
14

Help !Which of the following describes the function x4 − 3?

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
7 0
D. the degree of x4-3
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Lunna [17]

Answer:

the solution for x is x=40

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3 years ago
Select two ratios that are equivalent to 4:18
fredd [130]

36:8, 9:2, and 72: 16

Step-by-step explanation:

two ratios that are equivalent to 4:18

36:8, 9:2, and 72: 16

would all be equivalent. In order to find ratios that are equivalent to 18:4, you have to multiply both numbers by the same factor. For

8 0
3 years ago
To find the measure of ∠A in ∆ABC, use the___(Pythagorean Theorem, Law of Sines, Law of Cosines). To find the length of side HI
nadya68 [22]

<u>Part 1) </u>To find the measure of ∠A in ∆ABC, use

we know that

In the triangle ABC

Applying the law of sines

\frac{a}{sin\ A}=\frac{b}{sin\ B}=\frac{c}{sin\ C}

in this problem we have

\frac{a}{sin\ A}=\frac{b}{sin\ theta}\\ \\a*sin\ theta=b*sin\ A\\ \\ sin\ A=\frac{a*sin\ theta}{b} \\ \\ A=arc\ sin (\frac{a*sin\ theta}{b})

therefore

<u>the answer  Part 1) is</u>

Law of Sines

<u>Part 2) </u>To find the length of side HI in ∆HIG, use

we know that

In the triangle HIG

Applying the law of cosines

g^{2}=h^{2}+i^{2}-2*h*i*cos\ G

In this problem we have

g=HI

G=angle Beta

substitute

HI^{2}=h^{2}+i^{2}-2*h*i*cos\ Beta

HI=\sqrt{h^{2}+i^{2}-2*h*i*cos\ Beta}

therefore

<u>the answer Part 2) is</u>

Law of Cosines

3 0
3 years ago
Read 2 more answers
Find an equation in standard form for the hyperbola with vertices at (0, ±2) and foci at (0, ±7).
Alisiya [41]
<span>Standard Form of an Equation of an Hyperbola opening up and down is:

(y-k)^2 / b^2 - (x-h)^2 / a^2 = 1

</span><span>where Pt(h,k) is a center with vertices 'b' units up and down from center.

</span><span>vertices: vertices: (0,+-2) b = 2 AND Center is (0,-0)

(y)^2/4-(x)^2/a^2=1

</span><span>foci: (0,+-7) 

a^2 = 24 

square root of 4 + a^2 = 5.29

4 + 5.29 = 9.29

y^2 / 4 - x^2 / 24 = 1</span>
5 0
3 years ago
Read 2 more answers
Consider the line x-2y=-1 What is the slope of a line parallel to this line? What is the slope of a line perpendicular to this l
Paul [167]

Answer:

slope of line that is parallel is 1/2

slope of line that is perpendicular is -2

Step-by-step explanation:

parallel lines have the same slope

perpendicular lines have slopes that are opposite and reciprocal

x - 2y = -1

-2y = -x -1

y = 1/2x + 1/2

the coefficient of the 'x' term represents the slope

5 0
3 years ago
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