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2 years ago

How do you do this?

Mathematics

2 answers:

Alinara [238K]2 years ago

8 0

The left one is m=-1over2
the right is m=-1over -1

Flauer [41]2 years ago

6 0

Answer:

Step-by-step explanation: Use the slope formula which is y2-y1

x2-x1

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According to the histogram of travel times to work from the US 2000 census (Page 6 of "Journey to Work: 2000"), roughly what per

erastovalidia [21]

Histograms are used to represent data, where the length of each bar represents the frequency of the data element

The histogram is not given; So, I will give a general explanation.

Assume that the number of commuters that travel more than 45 minutes is 450, while the total number of commuters surveyed is 500.

The percentage of commuters that travel more than 45 minutes is the quotient of the commuters that travel more than 45 minutes and the total number of surveyed commuters.

So, we have:

$\%Percentage = \frac{450}{500}$

Divide 450 by 500

$\%Percentage = 0.9$

Express as percentage

$\%Percentage = 90\%$

Hence, the percentage of commuters that travel more than 45 minutes is 90%

Read more about histograms at:

brainly.com/question/2776232

7 0

1 year ago

Please help fast PLEASEEEE

AysviL [449]

Answer:

sorry can't help search it up on the internet

Step-by-step explanation:

6 0

2 years ago

Two numbers are in the ratio 3:7

lbvjy [14]

Answer:

98 And 18 i think

Step-by-step explanation:

8 0

2 years ago

The deposits Ginny makes at her bank each month form an arithmetic sequence. The deposit for month 3 is $150, and the deposit fo

givi [52]

1. 15 dollars
2. Deposit=15*month+105
3. Deposit=15*12+105=$285
4.
500=15*month+105
395=15*month
26.33=month
Round up to 27 for the nearest whole month, so month 27.

Hope this helps!

5 0

2 years ago

Read 2 more answers

Find the angle between u =the square root of 5i-8j and v =the square root of 5i+j.

fenix001 [56]

Answer:

The angle between vector $\vec{u} = 5\, \vec{i} - 8\, \vec{j}$ and $\vec{v} = 5\, \vec{i} + \, \vec{j}$ is approximately $1.21$ radians, which is equivalent to approximately $69.3^\circ$ .

Step-by-step explanation:

The angle between two vectors can be found from the ratio between:

their dot products, and
the product of their lengths.

To be precise, if $\theta$ denotes the angle between $\vec{u}$ and $\vec{v}$ (assume that $0^\circ \le \theta < 180^\circ$ or equivalently $0 \le \theta < \pi$ ,) then:

$\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ .

<h3>Dot product of the two vectors</h3>

The first component of $\vec{u}$ is $5$ and the first component of $\vec{v}$ is also

The second component of $\vec{u}$ is $(-8)$ while the second component of $\vec{v}$ is $1$ . The product of these two second components is $(-8) \times 1= (-8)$ .

The dot product of $\vec{u}$ and $\vec{v}$ will thus be:

$\begin{aligned} \vec{u} \cdot \vec{v} = 5 \times 5 + (-8) \times1 = 17 \end{aligned}$ .

<h3>Lengths of the two vectors</h3>

Apply the Pythagorean Theorem to both $\vec{u}$ and $\vec{v}$ :

$\| u \| = \sqrt{5^2 + (-8)^2} = \sqrt{89}$ .
$\| v \| = \sqrt{5^2 + 1^2} = \sqrt{26}$ .

<h3>Angle between the two vectors</h3>

Let $\theta$ represent the angle between $\vec{u}$ and $\vec{v}$ . Apply the formula $\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ to find the cosine of this angle:

$\begin{aligned} \cos(\theta)&= \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} = \frac{17}{\sqrt{89}\cdot \sqrt{26}}\end{aligned}$ .

Since $\theta$ is the angle between two vectors, its value should be between $0\; \rm radians$ and $\pi \; \rm radians$ ( $0^\circ$ and $180^\circ$ .) That is: $0 \le \theta < \pi$ and $0^\circ \le \theta < 180^\circ$ . Apply the arccosine function (the inverse of the cosine function) to find the value of $\theta$ :

$\displaystyle \cos^{-1}\left(\frac{17}{\sqrt{89}\cdot \sqrt{26}}\right) \approx 1.21 \;\rm radians \approx 69.3^\circ$ .

3 0

2 years ago

How do you do this?​

How do you do this?