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ExtremeBDS [4]
3 years ago
12

PLS HELP I WILL DO ANYTHING

Mathematics
1 answer:
Lunna [17]3 years ago
4 0

Answer:

the solution for x is x=40

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Evaluate 9÷3[(20-7)-2^2]
german

Answer:

43

Step-by-step explanation:

You will have to use the PEMDAS rule here. so Parntheses goes first, then exponents, then mutiplicaton or division, and finally addition or subtraction.

20-7= 13

-2^2 = (-2 * -2) = 4

9/3 = 3

so... 13*3 = 39+4 =43

3 0
3 years ago
Paulie ordered 250 pens and 250 pencils to sell for a theatre club fundraiser. The pens cost 11 cents more than the pencils. If
Korolek [52]
Remember that cents has a decimal when put in an equation.
250(x + 11) + 250x = 4250
250x + 2750 + 250x = 4250
500x + 2750 = 4250
500x = 1500
x = 3 cents (pencils)
x+11 = 14 cents (pens)
4 0
3 years ago
Adam divides 32/8032. In which place should he write the first digit of the quotient?
kow [346]

Answer:

We have a quotient between a 2 digit number and a 4 digit number.

The usual rule for this type of problems is:

If the denominator has n more digits than the numerator, then the first digit will be in the nth position at the right of the decimal point.

If also, the denominator is larger than the numerator times 10^n, then the decimal will be moved another place to the right.

For example, if we divide 10 by 100 we have:

10/100

The denominator has one more digit than the numerator, then n = 1.

this means that the first digit of the quotient, will be on the first place at the left of the decimal point.

We can solve the quotient to get:

10/100 = 0.1

And, as we predicted, the first decimal is in the first place.

Now, with our quotient we have:

32/8032

n = 2.

and:

32*10^n = 3200

The denominator is larger than this, then we will move the first decimal to another place to the right.

Then we should expect to have the first decimal in the third place after the decimal point.

We can solve the quotient to get:

32/8032 = 0.0039

As we expected.

3 0
2 years ago
Solve the equation. 10(x + 4) = 30 –1 3 –37 7
Flauer [41]

Assignment: \bold{Solve \ Equation: \ 10\left(x+4\right)=30}

<><><><><>

Answer: \boxed{\bold{x=-1}}

<><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><>

[ Step One ] Divide Both Sides By 10

\bold{\frac{10\left(x+4\right)}{10}=\frac{30}{10}}

[ Step Two ] Simplify

\bold{x+4=3}

[ Step Three ] Subtract 4 From Both Sides

\bold{x+4-4=3-4}

[ Step Four ] Simplify

\bold{x=-1}

<><><><><><><>

\bold{\rightarrow Mordancy \leftarrow}

6 0
3 years ago
An airline has a policy of booking as many as 150 persons on a plane that seats 140. past studies indicate that only 85% of book
RUDIKE [14]
Binomial distribution will be used to model situation because all following criteria are satisfied:
1. Bernoulli trials, i.e. exactly two possible outcomes (show up or not)2. Number of trials is known before and constant throughout the experiment, i.e. independent of outcomes (150 booked)3. All trials are independent of each other. (assumed from context)4. Probability of success is known, and remain constant throughout trials. (85%)Since all criteria are satisfied, we can model with binomial distribution, where the probability of x successes out of N trials each with probability of success p is given byP(x)=C(N,x)(p^x)(1-p)^(N-x)and,C(N,x) is number of combinations of selecting x objects out of N.
P(>140)=P(141)+P(142)+...+P(150)
=.00035620+0.00012783+0.00004056+0.00001117+0.00000262+0.00000051+0.00000008+0.00000001+0.00000000
=0.00053907

The above calculation is not very practical unless we have a statistical calculator or a software.

For practical hand calculations, we usually use the binomial approximation.
mean=np=150*0.85=127.5
variance = np(1-p)=150*.85*.15=19.125  (>10, possible to use binomial approximation, but accuracy is marginal).
We also need to use the continuity correction, which means that the portion above 140 is counted as 140.5 to 150 passengers.  Then we calculate
Z=(140.5-127.5)/sqrt(19.125)=2.973
P(x>=140.5)
=P(z>=Z)
=1-P(z<Z)
=1-P(z<2.973)
=1-0.99852
=0.00148
The answer is quite a bit off from the exact value of 0.000539, but an approximation is an approximation especially for skew distribution like in the present case (p=0.85 far from 0.5, and x=140 far from mean).
3 0
3 years ago
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