<span>First figure out how
many people there are all together. So mrs and mr is 2 there three
children so 2+3=5 so next round 179 to 200 and multiply 200x5. To do
that you can use the mental math way witch would be to take the whole
number out of 200 and make it 2. Then take the 5 in 200x5 and multiply
2x5. Then add the 2 zeros there were. And your estamated answer would be
1,000.
2+3=5
179=200
200x5
2x5=10
1,000
To figure out your real answer you will have to take 179 and multiply it by 5 so it will look like this:
34
179
x
5
895
Soto conculde the answer would be:
Estamated: $1,000
Exact: $895
Hope this helps!</span>
We are given dimensions of model and actual figure.
model: 9.5cm actual : 30.5m.
We need to find the length of actual shape for the scale factor 5cm.
Let us assume actual length be x m.
Let us set a proportion now.
<h3>5 : x = 9.5 : 30.5</h3>
Let us convert proportion into fractions.
On cross multiplying, we get
9.5x = 5× 30.5
9.5x = 152.5.
On dividing both sides by 9.5, we get
x=16.05.
<h3>Therefore, the scale factor for a model is 5cm= 16.05 m.</h3>
Answer:
12+4/8
Step-by-step explanation:
sum means add and you need to divide 8 by whatever 12 and 4 equal
12+4= 16
16/8=2
2
The difference between Tucker and Karly's take is that Tucker's solution is analytical while Karly's is graphical. But both are correct either way.
For Tucker's solution, let's say at x=-3 the value for y is 4, and at x=3, the value of y is still 4, then the average rate of change or slope is 0. Note that the slope of the curve is Δy/Δx. Since there is no change for Δy, the slope is zero.
For Karly's solution, even if the curve travels high or low but would have the same elevation of x=-3 and x=3, the average rate of change is still zero. It is actually just same with Tucker's but Karly just verbalizes her solution that was observed visually.
We'll use standard labeling of right triangle ABC, C=90 degrees, legs a, b, hypotenuse c.
11.
Right triangle, cliff peak A, boat B, angle opposite cliff is B=28.9 deg. adjacent leg a=65.7 m, cliff height is leg b.
tan B = b/a
b = a tan B = 65.7 tan 28.9° = 36.3 m
12.
Similar story, boat at B, opposite b=3.5 m, rope c=12 m
sin B = b/c
B = arcsin b/c = arcsin (3.5/12) = 17.0°
13.
c=124 m, A=58°
sin A = a/c
a = c sin A = 124 sin 58 = 105.2 m
14.
That's a hypotenuse c=4-1.2 = 2.8 m to a height b=1.8m so
cos A = b/c
A = arccos b/c = arccos (1.8/2.8) = 50.0°
15.
Not a right triangle, an isosceles triangle. Half of it is a right triangle with hypotenuse one arm, c=9.8 cm and angle opposite half the base of B=62/2=31°. We're after d=2b:
sin B = b/c
b = c sin B
d = 2b = 2 c sin B = 2(9.8) sin 31 = 10.1 cm
Almost equilateral
