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olchik [2.2K]
3 years ago
11

Find the value of x. rounded to the nearest tenth or as a whole/ fraction

Mathematics
1 answer:
lisov135 [29]3 years ago
8 0

Answer:

7.1

Step-by-step explanation:

Since we know this is isosceles triangle (right angle 90 and two 45 degree angles) we know side a and b are equal.

a^2 + b^2 = c^2

5^2 + 5^2 = c^2

25+25= c^2

50 = c^2

c = 7.071 rounded to 7.1

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Is negative three a perfect cube?
erik [133]

No, it is not a perfect cube. A perfect cube is a number that is obtained when you cube an integer. For example, 8 (cube of 2), 27 (cube of 3) and 64 (cube of 4). Since -3 cannot be obtained by cubing an integer, it is not a perfect cube.

6 0
3 years ago
Agora chess club has 16 members and gains a new memeber every month. The key club has 4 members and gains 4 new members every mo
svlad2 [7]

Answer:

For chess club:

y1 = 16 + 1*x where y1=total number of members after x months  

For film club

y2 = 4 + 4*x where y2=total number of members after x months  

y1 = y2 at  

16 + x = 4 + 4x

3x = 12  

x = 4  

Therefore, after 4 months they the same number of members (equals 20 members, 16 + 1*4 or 4 + 4*4).


3 0
3 years ago
What is the number of diagonals that intersect at a given vertex of a hexagon, heptagon, 30-gon and n-gon?
DENIUS [597]

Answer:

i. 9

ii. 14

iii. 405

iv. \frac{n(n-3)}{2}

Step-by-step explanation:

The number of diagonals in a polygon of n sides can be determined by:

\frac{n(n-3)}{2}

where n is the number of its sides.

i. For a hexagon which has 6 sides,

number of diagonals = \frac{6(6-3)}{2}

                                   = \frac{18}{2}

                                   = 9

The number of diagonals in a hexagon is 9.

ii. For a heptagon which has 7 sides,

number of diagonals = \frac{7(7-3)}{2}

                                   = \frac{28}{2}

                                   = 14

The number of diagonals in a heptagon is 14.

iii. For a 30-gon;

number of diagonals = \frac{30(30-3)}{2}

                                          = \frac{810}{2}

                                         = 405

The number of diagonals in a 30-gon is 405.

iv. For a n-gon,

number of diagonals = \frac{n(n-3)}{2}

The number of diagonals in a n-gon is \frac{n(n-3)}{2}

7 0
3 years ago
The owner of a quick oil-change business charges
Mkey [24]

Answer:

the sun is actually a planet

Step-by-step explanation:

8 0
3 years ago
Solving an equation involving complementary or supplementary angles! Please help I really would appreciate it
Schach [20]
2x + x + 33 = 90
3x + 33 = 90
3x = 57
x = 19
Angle 1 = 38°
Angle 2 = 52°
8 0
3 years ago
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