Answer:
x = -1
, y = 5
Step-by-step explanation:
Solve the following system:
{5 x + 3 y = 10 | (equation 1)
x = y - 6 | (equation 2)
Express the system in standard form:
{5 x + 3 y = 10 | (equation 1)
x - y = -6 | (equation 2)
Subtract 1/5 × (equation 1) from equation 2:
{5 x + 3 y = 10 | (equation 1)
0 x - (8 y)/5 = -8 | (equation 2)
Multiply equation 2 by -5/8:
{5 x + 3 y = 10 | (equation 1)
0 x+y = 5 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{5 x+0 y = -5 | (equation 1)
0 x+y = 5 | (equation 2)
Divide equation 1 by 5:
{x+0 y = -1 | (equation 1)
0 x+y = 5 | (equation 2)
Collect results:
Answer: {x = -1
, y = 5
54 55 59 61 61 62 68 70 72
First put your numbers in order from least to greatest. This shows your minimum is 54 and maximum is 72.
In the middle of the data set is 61.
54 55 59 61. 61. 62 68 70 72
To find the first qaurtile only use the numbers before rhe median (54 55 59 61) and find the median of that. Since 55 and 59 are both in the middle add them both and divide by two to find the middle lf those two numbers. You should get 57. So 57 is the first quartile.
Do the same steps with the numbers after the meadian for your third quartile. You should get 69 as your answer for the third quartile.
Answer:
5 pounds of TuRkEy BrEaSt
Step-by-step explanation:
Oooh, looks fun
ok
erm
we might want to know some properties


if

where a=a, then assume m=n

so



minus 17*2^x both sides

use u subsitution, u=2ˣ

solve

or

ac method
2 times 8=16
what 2 number multiply to get -17 and add to get 16
-16 and -1
2u²-1u-16u+8=0
(2u²-1u)+(-16u+8)=0
u(2u-1)+(-8)(2u-1)=0
(u-8)(2u-1)+0
u-8=0
u=8
2u-1=0
2u=1
u=1/2
now
u=2ˣ
8=2ˣ

3=x
and


-1=x
x=-1 and 3
neat problem
Answer:

Step-by-step explanation:
The nine coordinates are
,
, 
To find the line that best fit the data is to substitute the values in this equation
where
and 
Using the values from the table attached below, we can substitute and find the values of a and b
Substituting the values of a, we get,

Similarly, substituting the values of b, we get,

Thus, substituting the values of a and b in the formula, we get,
