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vazorg [7]
4 years ago
7

For rhombus LMNO, m∠LON = 102° and NP = 5 units. Use the diagram of rhombus LMNO to find the missing measures. The measure of ∠L

PM is °. The measure of ∠PMN is °. The length of LN is units.
Mathematics
2 answers:
aivan3 [116]4 years ago
8 0
LPM = 90

PMN = 51

LN = 10
Phantasy [73]4 years ago
8 0

Answer: angle LPM = 90, angle PMN = 51, side LN = 10

Explanation: Since, In case of rhombus, Diagonals bisect each other with the angle of 90, and corresponding angles are equal.

Here, In rhombus LMNO

\angle LON=\angle PMN = 102° (because both are corresponding angles)

⇒ \angle PMN =\angle LMN/2=102°/2

⇒\angle LPM =51°

Now, \angle LPM=90°

and, LN=LP+PN=5+5=10 unit.



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Hatshy [7]

Answer:

The coordinates of HF are (1, 4)

Step-by-step explanation:

The parameters of the line are;

The coordinate of the end points are H = (-11, 7), and J = (5, 3)

The ratio by which the point F divides the line = 3:1

The segments in the line are HF, and FJ

Therefore;

The fraction of the length of HJ that is represented by HF = 3/(3 + 1) × HJ = 3/4 × HJ

HF = 3/4 × HJ

Which gives the coordinates of the point F as follows;

Coordinate of F = (-11 +(5 - (-11))×3/4, 7 + (3 - 7)×3/4) =  (1, 4)

The coordinates of F are (1, 4)

We check the length of HF, from the equation for the length to of a line to get;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

l_{HF} = \sqrt{\left (4-7  \right )^{2}+\left (1-(-11)  \right )^{2}} = \sqrt{\left (-3  \right )^{2}+\left (12  \right )^{2}} = 3\cdot \sqrt{17}

Similarly, we check the length of HJ, to get;

l_{HF} = \sqrt{\left (3-7  \right )^{2}+\left (5-(-11)  \right )^{2}} = \sqrt{\left (-4  \right )^{2}+\left (16  \right )^{2}} = 4\cdot \sqrt{17}

The length of HF = 3·√(17)

The length of HJ = 4·√(17)

Therefore, from HF = 3/4× HJ, we have;

HF = 3/4 × 4·√(17) = 3·√(17)

Therefore, the coordinates of HF are (1, 4)

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Answer:

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