Ask question

Ask question

All categories

3 years ago

7

For rhombus LMNO, m∠LON = 102° and NP = 5 units. Use the diagram of rhombus LMNO to find the missing measures. The measure of ∠L

PM is °. The measure of ∠PMN is °. The length of LN is units.

2 answers:

aivan3 [116]3 years ago

8 0

LPM = 90

PMN = 51

LN = 10

Phantasy [73]3 years ago

8 0

Answer: angle LPM = 90, angle PMN = 51, side LN = 10

Explanation: Since, In case of rhombus, Diagonals bisect each other with the angle of 90, and corresponding angles are equal.

Here, In rhombus LMNO

$\angle LON=\angle PMN$ = 102° (because both are corresponding angles)

⇒ $\angle PMN =\angle LMN/2$ =102°/2

⇒ $\angle LPM$ =51°

Now, $\angle LPM$ =90°

and, LN=LP+PN=5+5=10 unit.

You might be interested in

Name and describe the methods for determining a marketing budget.

Mekhanik [1.2K]

Answer: There are several ways in which we can determine our marketing budget. Some of these are given below:

<u><em>1. Percentage of revenues:</em></u>

Under this method we usually take a fixed percentage of our revenues and further allocating this amount for marketing. We will choose the percentage that works best for us.

<u><em>2. Percentage of net sales:</em></u>

This method determines our marketing budget as a fraction of our net sales. This method will take a lot of trial and error to find the percentage that works well for our company.

<u><em>3. Industry specific:</em></u>

Nowadays, industries have specific projections as to the amount they will need to spend on marketing . The best way to get these numbers is to find a firm that represents our industry and ask them to provide us with averages. We can then refine the actual costs.

<em><u>4. Objective/task oriented </u></em>

This is model that works by setting out goals, planning out the tasks and then estimating the cost for all of these tasks. It works greatly for firms who have a immense knowledge about measurements and information of their business processes.

4 0

3 years ago

Identify intervals on which the function is increasing, decreasing, or constant.

tigry1 [53]

G ( x ) = 2 - ( x - 7 )²
g ( x ) = 2 - ( x² - 14 x + 49 )
g ( x ) = 2 - x² + 14 x - 49
g ( x ) = - x² + 14 x - 47
The maximum of the function is at:
x= - b / 2 a
x = - 14 / ( - 2 ) = 7
Therefore the function is increasing form x ∈ ( - ∞, 7 ) and decreasing for x ∈ ( 7, +∞ ).
Answer:
C. increasing, x < 7; decreasing x > 7.

3 0

2 years ago

An ellipse has a center at the origin, a vertex along the major axis at (0, 17), and a focus at (0, −8). Which equation represen

Marianna [84]

We know that
<span>Since the focus and vertex are above and below each other, rather than side by side, I know that this ellipse must be taller than it is wide.
</span>Then
a²<span> will go with the </span>y<span> part of the equation
</span>Also, since the focus is 8 <span>units below the center, then </span><span>c = 8
</span>since the vertex is 17<span> units above, then </span><span>a = 17
</span>The equation b²<span> = a</span>²<span> – c</span>²<span> gives me
</span>b²=17²-8²-----> b²=225
the equation is
y²/a²+x²/b²=1------> y²/289+x²/225=1

the answer is
y²/289+x²/225=1

see the attached figure

7 0

3 years ago

Read 2 more answers

A cylinder with a radius of 6cm and height of 15 cm has a cylindrical cut out of the

suter [353]

Answer:

$V = 518cm^3$

Step-by-step explanation:

Given

$h = 15cm$

$R = 6cm$

$r =5cm$

Required

The volume of the remaining cylinder

Before the cut-out, the cylinder has a volume (V) of:

$V = \pi R^2h$

After the cut-out, the cylinder has a volume of:

$V = \pi [R^2 -r^2]h$

So, we have:

$V = 3.14* [6^2 -5^2]*15$

$V = 3.14* [36 -25]*15$

$V = 3.14* 11*15$

$V = 518cm^3$

6 0

2 years ago

Engineers must consider the diameters of heads when designing helmets. The company researchers have determined that the populati

IrinaK [193]

Answer:

1. The minimum head breadth that will fit the clientele is of 3.95-in.

2. The maximum head breadth that will fit the clientele is of 9.25-in.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 6.6-in and a standard deviation of 1.1-in.

This means that $\mu = 6.6, \sigma = 1.1$

1. What is the minimum head breadth that will fit the clientele?

The 0.8th percentile, which is X when Z has a p-value of 0.008, so X when Z = -2.41.

$Z = \frac{X - \mu}{\sigma}$

$-2.41 = \frac{X - 6.6}{1.1}$

$X - 6.6 = -2.41*1.1$

$X = 3.95$

The minimum head breadth that will fit the clientele is of 3.95-in.

2. What is the maximum head breadth that will fit the clientele?

The 100 - 0.8 = 99.2nd percentile, which is X when Z has a p-value of 0.992, so X when Z = 2.41.

$Z = \frac{X - \mu}{\sigma}$

$2.41 = \frac{X - 6.6}{1.1}$

$X - 6.6 = 2.41*1.1$

$X = 9.25$

The maximum head breadth that will fit the clientele is of 9.25-in.

8 0

2 years ago