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Natali [406]
3 years ago
6

Question 6 (1 point)

Mathematics
1 answer:
faust18 [17]3 years ago
7 0

Answer:

12.....

Step-by-step explanation:

yeah that one

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Help show work btw I’ll give brainly
Juli2301 [7.4K]

Answer:

5 5/8

Step-by-step explanation:

also in a sec imma comment again the work so hold up

8 0
2 years ago
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The recommended single dose for a particular drug is 100 mg. How many doses can be obtained from 20 grams of the drug?
Lisa [10]

Answer:

B. 200 doses

Step-by-step explanation:

Given,

1 dose is required for 100 mg,

Since, 1 mg = 0.001 g,

⇒ 100 mg = 0.1 g

⇒ 1 dost is required for 0.1 g,

Thus, the ratio of doses and quantity ( in gram ) is \frac{1}{0.1}=10

Let x be the doses required for 20 grams,

So, the ratio of doses and quantity is \frac{x}{20}

\implies \frac{x}{20}=10

\implies x=200

Hence, 200 doses can be obtained from 20 grams of the drug.

Option 'B' is correct.

8 0
2 years ago
This is a pre calculus question that I need help with, serious answer PLEASE and thank you! Will give brainliest.
IRISSAK [1]

The wording of this question is a bit confusing... You can't write a sequence in sigma notation, but rather a series or sum. I think the question is asking you to write the sum of the sequence,

\dfrac12,\dfrac14,\dfrac18,\ldots,\dfrac1{64}

which would be

\dfrac12+\dfrac14+\dfrac18+\cdots+\dfrac1{64}

in sigma notation.

To do this, notice that the denominator in each term is a power of 2, starting with 2^1=2 and ending with 2^6=64. So in sigma notation, this series is

\displaystyle\sum_{n=1}^6\frac1{2^n}

4 0
3 years ago
Jesse worked forty hours this past week assuming he makes $12 an hour how much was withheld from his paycheck by his employer fo
Alecsey [184]
He made 12*40=480 dollars in total. 0.0765*480=36.72 dollars were withheld.
6 0
3 years ago
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Number 11 and 12. Solve for x and y. Please and thank you.
vlada-n [284]

Answer:

11. x=18, y=5

12. x=17, y=9

Step-by-step explanation:

Use the angle property https://www.proprofs.com/quiz-school/story.php?title=angle-properties-parallel-lines (REFER TO THIS LINK)

4 0
1 year ago
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