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Feliz [49]
4 years ago
7

A scale model of an office building is 3' x 2' x 5' (length, width, height). If the actual building has a length of 45 feet, wha

t is the volume of the actual building?
A)81,000 cubic feet

B)102,150 cubic feet

C)101,250 cubic feet

D)30,000 cubic feet
Mathematics
1 answer:
Finger [1]4 years ago
5 0

Answer:

C 101,250

Step-by-step explanation:

divide 45 by 3 its 15 so do 15x2 and 15x5 and multiply those together to find the volume

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According to VSEPR theory, if there are five electron domains in the valence shell of an atom, they will be arranged in a(n) ___
andriy [413]

Answer:

trigonal bypyramidal

Step-by-step explanation:

It's difficult to explain without a drawing or a model, but it would basically arrange itself into two triangle based pyramids connected to each other at the base, which is trigonal bypyramidal.

5 0
3 years ago
PLS HELP ME!!! The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of
Pachacha [2.7K]

Hello!

The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter your answer in the box. cm³

Data: (Cone)

h (height) = 12 cm

r (radius) = 4 cm (The diameter is 8 being twice the radius)

Adopting: \pi \approx 3.14

V (volume) = ?

Solving: (Cone volume)

V = \dfrac{ \pi *r^2*h}{3}

V = \dfrac{ 3.14 *4^2*\diagup\!\!\!\!\!12^4}{\diagup\!\!\!\!3}

V = 3.14*16*4

\boxed{V = 200.96\:cm^3}

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 4 cm

Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4* \pi * \dfrac{r^3}{3} , but we have a hemisphere, so the formula will be half the volume of the hemisphere V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}

Formula: (Volume of the hemisphere)

V = 2* \pi * \dfrac{r^3}{3}

Solving:

V = 2* \pi * \dfrac{r^3}{3}

V = 2*3.14 * \dfrac{4^3}{3}

V = 2*3.14 * \dfrac{64}{3}

V = \dfrac{401.92}{3}

\boxed{ V_{hemisphere} \approx 133.97\:cm^3}

What is the approximate volume of this figure?

Now, to find the total volume of the figure, add the values: (cone volume + hemisphere volume)

Volume of the figure = cone volume + hemisphere volume

Volume of the figure = 200.96 cm³ + 133.97 cm³

\boxed{\boxed{\boxed{V = 334.93\:cm^3 \to Volume\:of\:the\:figure \approx 335\:cm^3 }}}\end{array}}\qquad\quad\checkmark

Answer:

The volume of the figure is approximately 335 cm³

_______________________

I Hope this helps, greetings ... Dexteright02! =)

8 0
3 years ago
Read 2 more answers
Can anyone help me out with this question? It doesn’t have to be a long answer, just a couple sentences. Thanks! ❤️
s2008m [1.1K]

Answer:

Step-by-step explanation:

I think both are the same because you have equations in the formula and what ever you do on one side you do to the other.

6 0
3 years ago
What is the quotion of 5/6 divided by 5/24
Sloan [31]

Step-by-step explanation:

remember, dividing one fraction by a second is the same as multiplying the first one with the inverse fraction of the second.

5/6 ÷ 5/24 = 5/6 × 24/5 = 24×5 / 6×5 = 24/6 = 4

5 0
3 years ago
What is the range of y=|2x-1|
zepelin [54]

Answer:

[0,∞) {y║y≥0}

Step-by-step explanation:

The absolute value expression has a V shape. The range of a positive absolute value expression starts at its vertex and extends to infinity.

3 0
3 years ago
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