the answer for this is 84915
Step-by-step explanation:
Draw diagonal AC
The triangle ABC has sides 17 and 25
Say AB is 17, BC is 25
Draw altitude on side BC from A , say h
h = 17 sin B
Area = 25*17 sin B = 408
sin B = 24/25
In ∆ ABC
Cos B = +- 7/25
= 625 + 289 — b^2 / 2*25*17
b^2 = 914 — 14*17 = 676
b = 26
h = 17*24/25 = 408/25 = 16.32
Draw the second diagonal BD
In ∆ BCD, draw altitude from D, say DE =h
BD^2 = h^2 + {(25 + sqrt (289 -h^2) }^2
BD^2 = 16.32^2 + (25 + 4.76)^2
= 885.6576 + 266.3424
BD = √ 1152 = 33.94 m
Answer:
(x+5)²(x²+5)
Step-by-step explanation:
Given two functions x²+5 and x²+10x+25, to get their Lowest common factor, we need to to first factorize x²+10x+25
On factorising we have:
x²+5x+5x+25
= x(x+5) +5(x+5
= (x+5)(x+5)
= (x+5)²
The LCM can be calculated as thus
| x²+5, (x+5)²
x+5| x²+5, (x+5)
x+5| x²+5, 1
x²+5| 1, 1
The factors of both equation are x+5 × x+5 × x²+5
The LCM will be the product of the three functions i.e
(x+5)²(x²+5)
This hives the required expression.
Answer
1/3
hope this helps have a nice day:)
