(4x-3y)^2(4x-3y)
=(16x^2-24xy+9y^2)(4x-3y)
=64x^3-96x^2y+36xy^2-48x^2y+72xy^2-27y^3
=64x^2-144x^2y+108xy^2-27y^3
Answer:
The answer is 80 because 10x8 is 80 and the nearest 10 means it need to have a 0 behind so it is 80
You find its absolute value which is 11
Usually it's fun when you know what's going on....
