All categories

3 years ago

If a triangle has sides of lengths 14 cm and 5 cm, what must the 3rd side 5 points

Mathematics

1 answer:

iVinArrow [24]3 years ago

3 0

12 i think, not positive!

You might be interested in

Use the quadratic formula to solve 4x2 – 8x – 60 = 0. A. B. No solution C. x = 5, –3 D. x = –3/5, –1

Lelu [443]

Nothing further can be done with this solution

8 0

3 years ago

In a study of author productivity, a large number of authors were classified according to the number of articles they had publis

bekas [8.4K]

Answer:

Follows are the response to this question:

Step-by-step explanation:

It is the most important positive skewness of the data is the distribution.

Notes:

Another approach for Mini-tab to generate a graph from the data set is through the capability of Mini-tabs, for instance, to type 784(1) in 784 copies of its number 1, to input multiple copies of the same number. Frequency data were input with both the following attached file mini-tab directions in this workout:

7 0

3 years ago

Given the sequence below, what is the 9th term? 2, 1, 4, -1, 6, ...

jolli1 [7]

Answer:

The 9th term would be 10.

Step-by-step explanation:

Each of the odd terms is 2 more than the previous. We do not even need to look at the even terms to find the 9th one.

2, odd, 4, odd, 6, odd, 8, odd, 10

8 0

3 years ago

An English teacher needs to pick 9 books to put on his reading list for the next school year, and he needs to plan the order in

Nikitich [7]

Answer: $4.37\times10^3$

Step-by-step explanation:

Given : Number of choices for novels = 4

Number of choices for plays = 6

Number of choices for poetry books = 5

Number of choices for nonfiction books = 5

Total books =4+6+5+5=20

If he wants to include all 4 novels, then the number of books left to select = 9-4=5

Remaining choices for books = 20-4=16

Number of combinations of n things taking r at a time : $\dfrac{n!}{r!(n-r)!}$

Then, the number of different reading schedules are possible :_

$^4C_4\times^{16}C_5\\\\=\dfrac{4!}{4!(4-4)!}\times\dfrac{16!}{5!(16-5)!}\\\\=(1)\times\dfrac{16\times15\times14\times13\times12\times11!}{120\times11!}\\\\=4368=4.368\times10^3\approx4.37\times10^3$

Hence, the required answer is $4.37\times10^3$ .

8 0

3 years ago

Is the GCF of two even numbers 2

lions [1.4K]

No, GCF means greatest common factor, meaning the largest number than can be divided into the number. 2 would be the lowest common factor or LCF.
EX. 200 & 440. In this case the GCF would be 40, but the LCF would be 2 because they are both even numbers

3 0

4 years ago

Read 2 more answers