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kolezko [41]
3 years ago
12

What is 8 1/8 divided by 5/6

Mathematics
2 answers:
-BARSIC- [3]3 years ago
6 0
The answer of that is 39/4
mart [117]3 years ago
5 0

Answer:

9.75

Step-by-step explanation:

You might be interested in
2(x - 3) + 9 = 3(x + 1) + X?​
kow [346]

Answer:

x = -X    OR     x = 0

Step-by-step explanation:

I don't know if the capital 'X' was a different variable, so I did both calculations.

2(x - 3) + 9 = 3(x + 1) + X

= 2x - 6 + 9 = 3x + 3 + X

= 2x + 3 = X + 3x + 3

= -x = X

= x = -X

2(x - 3) + 9 = 3(x + 1) + x

= 2x - 6 + 9 = 3x + 3 + x

= 2x + 3 = 4x + 3

= -2x = 0

= x = 0

5 0
3 years ago
Describe the steps to copy angle CAB∠ C A B.
Anestetic [448]

Answer:

Step-by-step explanation:

Construction: To copy angle CAB.

i. On angle CAB, with center A and any radius; draw an arc to intersect CA at E and AB at F.

ii. Place a divider at EF to copy the angle.

iii. Draw a separate straight line MN of approximate length to AB.

iv. Mark point P on MN. Place the divider with radius EF at P to mark Q.

v. Draw a line LM from M through Q.

vi. Therefore, angle CAB would be equal to angle LMN.

7 0
4 years ago
Write the point-slope form of the equation of the line through the given point with the given
Marina86 [1]

Question 3)

Given

The point (1, -5)

The slope m = -5/6

Using the point-slope form of the equation of a line

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

In our case:

  • m = -5/6
  • (x₁, y₁) = (1, -5)

substituting the values m = -5/6 and the point (1, -5) in the point-slope form of the equation of the line

y-y_1=m\left(x-x_1\right)

y-\left(-5\right)=-\frac{5}{6}\left(x-1\right)

y+5=-\frac{5}{6}\left(x-1\right)

Thus, the point-slope form of the equation of the line is:

y+5=-\frac{5}{6}\left(x-1\right)

Question 4)

Given

The point (-1, 5)

The slope m = -7/2

In our case:

  • m = -7/2
  • (x₁, y₁) = (-1, 5)

substituting the values m = -7/2 and the point (-1, 5) in the point-slope form of the equation of the line

y-y_1=m\left(x-x_1\right)

y-5=-\frac{7}{2}\left(x-\left(-1\right)\right)

y-5=-\frac{7}{2}\left(x+1\right)

Thus, the point-slope form of the equation of the line is:

y-5=-\frac{7}{2}\left(x+1\right)

7 0
3 years ago
PLEASE HELP ME ILL MARK BRAINLYEST
mr_godi [17]
It’s 1/5 just put hem all together
3 0
3 years ago
Read 2 more answers
20 POINTS ILL MARK U BRAINLIEST PLS
makkiz [27]

Answer:

13 + \sqrt{89}

or

22.43398... (depends on how you round it)

Step-by-step explanation:

1. The question stated that the radius of the circle O is 5, so the length of AO and CO is 5.

2. Since line AB and line CB are both tangent to the circle, they have the same length. CB is 8, so AB will also be 8.

--> Both triangle AOB and COB share one side, and the other side (radius) has the same length, so the third side must be the same length

3. Tangent means having a 90-degree angle with the radius. We know that the triangle AOB is a right triangle since the angle OAB is 90 degrees.

We can use the Pythagorean theorem to find side OB. OB^2 = AO^2 + AB^2.

--> OB^2 = 25 + 64

--> OB^2 = 89

--> OB = \sqrt{89}

Now that we know the lengths of all three sides, we can add them up.

--> 5 + 8 + \sqrt{89}

--> 13 + \sqrt{89}

or

--> 22.43398113....

5 0
2 years ago
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