Answer:
x=2.4
Step-by-step explanation:
as the 2 triangles are similar,
therefore ;
T=2π/|b|. The period of an equation of the form y = a sin bx is T=2π/|b|.
In mathematics the curve that graphically represents the sine function and also that function itself is called sinusoid or sinusoid. It is a curve that describes a repetitive and smooth oscillation. It can be represented as y(x) = a sin (ωx+φ) where a is the amplitude, ω is the angular velocity with ω=2πf, (ωx+φ) is the oscillation phase, and φ the initial phase.
The period T of the sin function is T=1/f, from the equation ω=2πf we can clear f and substitute in T=1/f.
f=ω/2π
Substituting in T=1/f:
T=1/ω/2π -------> T = 2π/ω
For the example y = a sin bx, we have that a is the amplitude, b is ω and the initial phase φ = 0. So, we have that the period T of the function a sin bx is:
T=2π/|b|
Answer:
80° , 100°, 80°
Step-by-step explanation:
∠ 1 and ∠ 2 form a straight line and sum to 180° , then
2x + 40 + 2y + 40 = 180
2x + 2y + 80 = 180 ( subtract 80 from both sides )
2x + 2y = 100 → (1)
∠ 1 and ∠ 3 are vertical angles and are congruent , then
2x + 40 = x + 2y ( subtract x from both sides )
x + 40 = 2y ( subtract 40 from both sides )
x = 2y - 40 → (2)
Substitute x = 2y - 40 into (1)
2(2y - 40) + 2y = 100
4y - 80 + 2y = 100
6y - 80 = 100 ( add 80 to both sides )
6y = 180 ( divide both sides by 6 )
y = 30
Substitute y = 30 into (2)
x = 2(30) - 40 = 60 - 40 = 20
Thus x = 20 and y = 30
Then
∠ 1 = 2x + 40 = 2(20) + 40 = 40 + 40 = 80°
∠ 2 = 2y + 40 = 2(30) + 40 = 60 + 40 = 100°
∠3 = x + 2y = 20 + 2(30) = 20 + 60 = 80°
Answer:
-3/7
Step-by-step explanation:
Parallel lines have the same slope
If the green line has a slope of -3/7, the red line has a slope of -3/7
Answer:
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