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laiz [17]
3 years ago
14

Which strategy would not correctly solve this story problem?

Mathematics
1 answer:
konstantin123 [22]3 years ago
4 0
I believe it would be B.
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A plane can fly 300 miles in the same time as it takes a car to go 210 miles. If the car travels 90 mph slower than the plane, f
Rudiy27

Answer:

<em>210</em><em>/</em><em>{</em><em>s</em><em> </em><em>60</em><em>}</em>

<em>Answer</em><em> </em><em>is</em><em> </em><em>this</em><em> </em>

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3 years ago
Find the area of the parallelogram. *
saul85 [17]

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Step-by-step explanation:

30hg(jn

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3 years ago
13. Given the following historical data and weights of .5, .3, and .2, what is the three-period weighted moving average forecast
Ostrovityanka [42]

Answer:

b. 144.8

Step-by-step explanation:

When calculating the moving average estimate of an observation , each of the observations are usually computed with the same weighted . In some cases, it is  beneficial to assign different  weight on the observations  such that the observation closer to the time period being forecast, has higher weight.  This is refer to as weighted moving average technique. The sum of the individual weight in a weighted moving average technique must equal to 1.

The three-period weighted moving average forecast for period 5 = 144*0.5 + 148 *0.3 + 142 *0.2 =  144.8

4 0
4 years ago
Solve the compound inequality. 7x&gt;-35 and -5x&gt;-50
mafiozo [28]

Answer:

x > - 5

x < 10

Step-by-step explanation:

Divide 7x>-35 by 7

Divide - 5x>-50 by - 5

Since we divide by a negative whe change the inequality sign.

7 0
4 years ago
The scores for a certain test of intelligence are normally distributed with mean 85 and standard deviation 11. Find the 90th per
jonny [76]

Answer:

99.1 is the 90th percentile of these scores.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 85

Standard Deviation, σ = 11

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.90

P( X < x) = P( z < \displaystyle\frac{x - 85}{11})=0.90  

Calculation the value from standard normal z table, we have,  

P(z \leq 1.282) = 0.90

Putting values, we get,

\displaystyle\frac{x - 85}{11} = 1.282\\\\x = 99.1

Thus, 99.1 is the 90th percentile of these scores.

5 0
3 years ago
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