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mariarad [96]
2 years ago
5

The ratio of the length to the breadth of a rectangle is 7:3

Mathematics
1 answer:
diamong [38]2 years ago
3 0
No it’s not me it’s a
Ok ok ty
A
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El 1.5% de 2kg de azucar es:
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Convierte el porcentaje (0.015) y multiplica por 2

0.03 kg
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2 years ago
Three groups of a number plus two
Mkey [24]

Answer:

Step-by-step explanation:

This can be modelled with the variable x to represent the "groups"

3x + 2

Multiplifcation means groups of.

3x is 3 times x, which is 3 groups of x.

6 0
3 years ago
5,5,3 Is this a triangle? Explain.
Dimas [21]

Answer:

yes because if the two least numbers add up to be larger than the biggest number than its a triangle

yes

no

yes

Step-by-step explanation:

idk if this is right but I tried

4 0
3 years ago
Read 2 more answers
Simplify (7t^2+9)+(6t^2+8)<br>​
Alborosie

Answer:

13t^2 +17

Step-by-step explanation:

It helps to regroup the terms so like terms are together. Then you can more easily see how to combine them.

(7t^2 +9) + (6t^2 +8) = 7t^2 + 9 + 6t^2 + 8

= 7t^2 + 6t^2 + 9 + 8

= t^2·(7 + 6) + (9 +8)

= 13t^2 +17

8 0
3 years ago
Read 2 more answers
Two cars are driving towards an intersection from perpendicular directions.
FrozenT [24]

For a better understanding of the solution provided here please find the diagram in the attached file.

In the diagram, A is the intersection. B is the position of the first car and C is the position of the second car. As can be clearly seen, as per the directions given in the question, the cars and the intersection make a right triangle.

The distance between the first car and the intersection is x and the distance between the second car and the intersection is y. The distance between the two cars is depicted by s. As we can see, s is the hypotenuse of the right triangle. At the given instance the distances are 8 meters and 6 meters respectively. Thus, by the Pythagorean Theorem the hypotenuse will be:

s=\sqrt{8^2+6^2}= \sqrt{100}=10...............(Equation 1)

Now, we know that at any instant the Pythagorean Theorem holds and so we will have, in general:

s^2=x^2+y^2

Now, implicitly differentiating the above formula with respect to time, we get:

2s\frac{ds}{dt}=2x \frac{dx}{dt}+2y \frac{dy}{dt}

This can be further simplified by dividing both the sides by the common factor 2 as:

s\frac{ds}{st}=x \frac{dx}{dy}+y\frac{dy}{dt}.................(Equation 2)

As we can see from the questions and the diagram, \frac{dx}{dt}=-2 m/s and \frac{dy}{dt}=-9 m/s. The negative sign is there because the distances y and x are reducing as the cars approach the intersection.

Applying this knowledge to (Equation 2) along with the fact that as per (Equation 1), s=10, we get (Equation 2) to become:

10\times \frac{ds}{dt}=8\times -2+6\times -9=-70

Therefore, \frac{ds}{dt}= \frac{-70}{10}=-7 m/s

Thus,  the rate of change of the distance between the cars at the given instant (in meters per second) is -7.

Therefore, out of the given options, option D is the correct one.


4 0
3 years ago
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