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2 years ago

Please help me with math question

Mathematics

2 answers:

djverab [1.8K]2 years ago

8 0

M∠NQS = m∠BQS - m∠BQN = 78 - 48 = 30°

Marat540 [252]2 years ago

4 0

30 degrees
hope this helps if it really does please give me brainliest ^-^

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Find 4 consecutive odd numbers such that twice the sum of the least 2 numbers is 40 less than three times the sum of the greates

ANTONII [103]

4 consecutive odd numbers....x, x + 2, x + 4, x + 6

2(x + x + 2) = 3(x + 4 + x + 6) - 40
2(2x + 2) = 3(2x + 10) - 40
4x + 4 = 6x + 30 - 40
4x + 4 = 6x - 10
4x - 6x = -10 - 4
-2x = - 14
x = -14/-2
x = 7

x + 2 = 7 + 2 = 9
x + 4 = 7 + 4 = 11
x + 6 = 7 + 6 = 13

ur numbers are : 7,9,11,13 <==

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3 years ago

Can someone please help me with this question please please help me I really really need help please.

harina [27]

Answer:

1st : neither linear nor nonlinear

2nd: nonlinear

3rd: linear

4th: both linear and nonlinear

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2 years ago

The number of people who attended a school's last six basketball games increased as the team neared the state sectional games. T

Thepotemich [5.8K]

The function will be a (linear function) linear equation in two variable and the equation of the function is y = 87x - 783

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

We have given data:

Game(x): 13 14 15 16 17 18

Attendance(y): 348 435 552 609 696 783

If plot these points on a coordinate plane, we will see these points will align in a straight line.

We know we can find a line equation with two points:

(13, 348) and (14, 435)

$\rm (y - 435) = \dfrac{435-348}{14-13}(x-14)$

y - 435 =87(x-14)

y = 87x - 783

Thus, the function will be a (linear function) linear equation in two variable and the equation of the function is y = 87x - 783

Learn more about the linear equation here:

brainly.com/question/11897796

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2 years ago

The nth term of a sequence is 3n^2- 1

Thepotemich [5.8K]

Answer: The number that belongs to both sequences is 26.

Step-by-step explanation:

We have two sequences, let's call one as A and the other as B.

The n-th term of sequence A is written as:

aₙ = 3*n^2 - 1

the nth term of sequence B is written as:

bₙ = 30 - n^2

We want to find a term that belongs to both sequences, (it can be for different integers, we can use n for sequence A and x for sequence B)

Then we want to find:

aₙ = bₓ

where n and x are integer numbers.

Then we will heave:

3*n^2 - 1 = 30 - x^2

To find the pair, we could isolate one of the variables, then input different integers in the other variable and see if the outcome is also an integer.

Let's isolate n.

3*n^2 = 30 - x^2 + 1

3*n^2 = 31 - x^2

n^2 = (31 - x^2)/3

n = √( (31 - x^2)/3)

Now let's input different values for x, and see if the outcome is also an integer, notice that x is in a negative term inside a square root, then we have only a few values of x such that the equation can be true.

Then let's start with x = 1.

n(1) = √( (31 - 1^2)/3) = √(30/3) = √10

We know that √10 is not an integer.

now with x = 2,

n(2) = √( (31 - 2^2)/3) = √( (31 - 4)/3) = √(27/3) = √9 = 3

then if x = 2, we have n = 3.

Both of them are integers, then we get:

a₂ = 3*(3)^2 - 1 = 27 - 1 = 26

b₃ = 30 - 2^2 = 30 - 4 = 26

The number that belongs to both sequences is 26.

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2 years ago

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ICE Princess25 [194]

I believe the answer is D. let me know if im wrong

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