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Alexandra [31]
3 years ago
12

The label on a bottle shows the following information: C2H4O, molar mass 44.06 grams per mole. The formula must be:

Chemistry
2 answers:
Ivahew [28]3 years ago
5 0
The formula can be empirical because the subscripts are reduced to the lowest fraction. 

To check if this formula is also the molecular formula we can check by obtaining the molar mass of the compound it is equal to the given molar mass. Thus 

12*2 + 4*1 + 16 = 44 g/mol

this is ~equal to the given molar mass thus the given equation can be both empirical and molecular.
Alexandra [31]3 years ago
3 0

Answer:

c. the empirical formula and the molecular formula

Explanation:

Atomic mass of C = 12 amu

Atomic mass of H = 1.0 amu

Atomic mass of O = 16 amu

Molar mass of C₂H₄O = (12 x 2) + (1 x 4) + (16 x 1) = 44 g/mol

Molar mass is given by the summation of the atomic mass of the individual atoms.

We calculate the molecular mass or molar mass from the molar formula. therefore C₂H₄O is the molecular formula.  

Also empirical formula is the simplest ratio of the atoms in a molecule. For every 1 O atom there are 2 C atoms and 4 H atoms. So this is the simplest ratio of atoms in the molecule. Therefore, C₂H₄O is also the empirical formula.  

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7 0
3 years ago
what is the approximate area of a regular pentagon with a side lenghtt of 6 feet and a distance from the center to a vertex of 6
Degger [83]
A regular pentagon may be divided into 5 congruent triangles.


If the side of the pentagon is 6 feet, each base of the triangles will be 6 feet.


If the distance from the center to a vertex is 6 feet, all the sides of the triangles will 6 feet.


So there are 5 congruent, equilateral triangles each with side equal to 6 feet.


The area one of those triangles is calculateb by:


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3 years ago
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6 0
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Read 2 more answers
How many grams of a 23.4% by mass naf solution is needed if you want to have 1.33 moles of naf?
jenyasd209 [6]
Percentage by mass is the mass of NaF present in 100 g of the solution.
the percentage by mass of NaF is 23.4 %
this means that in 100 g of solution, mass of NaF present is 23.4 g
the number of moles of NaF present - 1.33 mol
mass of NaF - 1.33 mol x 42 g/mol = 55.9 g
when there's 23.4 g of NaF - mass of solution is 100 g
therefore when there's 55.9 g of NaF - mass of solution is 100 / 23.4 x 55.9 
= 239 g
mass of solution required is 239 g
6 0
4 years ago
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