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sladkih [1.3K]
3 years ago
5

A student wants to classify some household chemicals by testing them using litmus paper. If she is going to classify these chemi

cals correctly, which statement will best help her determine if the chemicals are acids or bases? *
if blue litmus paper turns red, the substance has a pH below 7 and is an acid
if blue litmus paper turns red, the substance has a pH above 7 and is a base
if blue litmus paper turns red, the substance has a pH below 7 and is a base
if blue litmus paper turns red, the substance has a pH above 7 and is an acid
Chemistry
1 answer:
Murrr4er [49]3 years ago
7 0

Answer:

its A

Explanation:

becasue when blue litmus paper turns red the substance has a pH level below 7,and when it stays blue it is above 7.

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Mg(OH)2 is a sparingly soluble salt with a solubility product, Ksp, of 5.61×10−11. It is used to control the pH and provide nutr
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Answer:

The ration of the molar solubility is 165068.49.

Explanation:

The solubility reaction of the magnesium hydroxide in the pure water is as follows.

Mg(OH)_{2}\Leftrightarrow Mg^{2+}(aq)+2(OH)^{-}(aq)

              [Mg^{2+}][OH^{-}]

Initial      0          0

Equili     +S       +2S

Final      S          2S

K_{sp}=[Mg^{2+}][OH^{-}]

5.61\times 10^{-11}=(S)(2S)^{2}

S=(\frac{5.61\times 10^{-11}}{4})^{1/3}=2.41\times 10^{-4}M

Solubility of Mg(OH)_{2} in 0.180 M NaOH is a follows.

Mg(OH)_{2}\Leftrightarrow Mg^{2+}(aq)+2(OH)^{-}(aq)

              [Mg^{2+}][OH^{-}]

Initial      0          0

Equili     +S       +2S

Final      S          2S+0.180M

K_{sp}=[Mg^{2+}][OH^{-}]

5.61\times 10^{-11}=(S)(2S+0.180)^{2}

S=1.46\times 10^{-9}M

Ratio\,of\,solubility=\frac{2.41\times 10^{-4}}{1.46\times 10^{-9}}=165068.49

Therefore, The ration of the molar solubility is 165068.49.

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