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Elodia [21]
3 years ago
10

What is the major difference between an attraction and entertainment?

Chemistry
2 answers:
EastWind [94]3 years ago
6 0
Attraction is something to go look at. Entertainment is something to do or watch.
Pani-rosa [81]3 years ago
5 0

This question is incomplete. Here is the complete question:

What is the major difference between an attraction and entertainment?

a. An attraction offers retail services.

b. An attraction always requires a paid admission.

c. An attraction can be part of a travel package.

d. An attraction is offered year-round.

Answer:

The correct answer is option c. An attraction can be part of a travel package.

Explanation:

When we talk about entertainment, we are referring to a type of amusement, or the action of providing an activity for this purpose.

While an attraction is something that usually draws attention to somewhere, or something. For example, if we hired a travel package, it would surely include an attraction of the place we are going to visit, and that is the major difference between both definitions.

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Explanation:

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3 years ago
Be sure to answer all parts.The equilibrium constant, Kc, for the formation of nitrosyl chloride from nitric oxide and chlorine,
djverab [1.8K]

<u>Answer:</u> The reaction proceeds in the forward direction

<u>Explanation:</u>

For the given chemical equation:

2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)

Relation of K_p\text{ with }K_c is given by the formula:

K_p=K_c(RT)^{\Delta n_g}

where,

K_p = equilibrium constant in terms of partial pressure = ?

K_c = equilibrium constant in terms of concentration = 6.5\times 10^4

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature = 35^oC=[35+273]K=308K

\Delta n_g = change in number of moles of gas particles = n_{products}-n_{reactants}=2-3=-1

Putting values in above equation, we get:

K_p=6.5\times 10^4\times (0.0821\times 500)^{-1}\\\\K_p=1583.43

K_p is the constant of a certain reaction at equilibrium while Q_p is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

The expression of Q_p for above equation follows:

Q_p=\frac{(p_{NOCl})^2}{p_{Cl_2}\times (p_{NO})^2}

We are given:

p_{NOCl}=1.76atm

p_{NO}=1.01atm

p_{Cl_2}=0.42atm

Putting values in above equation, we get:

Q_p=\frac{(1.76)^2}{0.42\times (1.01)^2}=7.23

We are given:

K_p=1583.43

There are 3 conditions:

  • When K_{p}>Q_p; the reaction is product favored.
  • When K_{p}; the reaction is reactant favored.
  • When K_{p}=Q_p; the reaction is in equilibrium

As, K_p>Q_p, the reaction will be favoring product side.

Hence, the reaction proceeds in the forward direction

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Explanation:

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