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3 years ago

Solve the Quadratic Equation.

Mathematics

1 answer:

vichka [17]3 years ago

7 0

Answer:

x = ± 2i

Step-by-step explanation:

The equation has no real roots, gut has complex roots

Given

x² = - 4 ( take the square root of both sides )

x = ± $\sqrt{-4}$

= ± $\sqrt{4(-1)}$

[ Note that $\sqrt{-1}$ = i ]

= ± $\sqrt{4}$ × $\sqrt{-1}$ = ± 2i

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A picture is 5 inches wide and 8 inches tall.

olganol [36]

Answer:

100 in^2

Step-by-step explanation:

Solve Area first:

5x8

= 40

Multiply by 2.5 (Enlarge)

40 x 2.5

= 100

6 0

3 years ago

Read 2 more answers

Is the perimeter of a square and its side length linear or not linear?

NARA [144]

Its linear , if side is x then perimeter is 4x
I hope this helps, if you have any further questions don't hesitate to ask

4 0

3 years ago

I need help thank you

Juliette [100K]

Answer:

Step-by-step explanation:

The key and the most critical step is to draw the line first. Don't do anything else before that.

(2,-8) (-2,-8)

What you find out is that the y value is always - 8.

So the line has no slope and any x value

y = 0*x + b

y = - 8 is the equation of the line.

8 0

3 years ago

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The length of a rectangle is three inches more than the width. the area of the rectangle is 180 inches. find the width of the re

ch4aika [34]

We have a rectangle with length L that is 3 inches more than the width W. Then we can write this as:

$L=W+3$

The area of the rectangle is 180 square inches.

We have to find the width W.

As the area is equal to the product of the length and the width, we can write this equation and solve for W as:

$\begin{gathered} A=180 \\ L\cdot W=180 \\ (W+3)\cdot W=180 \\ W^2+3W=180 \\ W^2+3W-180=0 \end{gathered}$

We have a quadratic equation. The roots of this equation will be the mathematical solutions.

We can find the roots using the quadratic formula:

$\begin{gathered} W=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ W=\frac{-3\pm\sqrt[]{3^2-4\cdot1\cdot(-180)}}{2\cdot1} \\ W=\frac{-3\pm\sqrt[]{9+720}}{2} \\ W=\frac{-3\pm\sqrt[]{729}}{2} \\ W=\frac{-3\pm27}{2} \\ W_1=\frac{-3-27}{2}=-\frac{30}{2}=-15 \\ W_2=\frac{-3+27}{2}=\frac{24}{2}=12 \end{gathered}$

The solutions are W = -15 and W = 12.

The first one is not valid, as W has to be greater than 0.

Then, the solution to our problem is W = 12 in.

Answer: the width is W = 12 inches.

6 0

1 year ago

Plz plz help

viktelen [127]

X^2 - 10 = 3x
X^2 - 3x - 10 = 0
(x - 5) (x + 2) = 0
x = 5 and x = -2
Answer: x = -2

6 0

3 years ago