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3 years ago

Solve the Quadratic Equation.

Mathematics

1 answer:

vichka [17]3 years ago

7 0

Answer:

x = ± 2i

Step-by-step explanation:

The equation has no real roots, gut has complex roots

Given

x² = - 4 ( take the square root of both sides )

x = ± $\sqrt{-4}$

= ± $\sqrt{4(-1)}$

[ Note that $\sqrt{-1}$ = i ]

= ± $\sqrt{4}$ × $\sqrt{-1}$ = ± 2i

You might be interested in

I am a decimal

dybincka [34]

0.6<2x<0.65 (because it's closer to 6)
0.3<x<0.325

Since the thousandths digit of 2x is 2, then the thousandths digit of x is 1 or 6, so the decimal could be 0.301, 0.302, 0.311, 0.312, 0.321

Hope this helps :)

6 0

3 years ago

Read 2 more answers

Is AB and CD parallel? Why/why not

adelina 88 [10]

Step-by-step explanation:

AB and CD is not parallel because co-interior sum is 180 and another reason is that parallel sign isn't given.

4 0

2 years ago

A random sample of 500 registered voters in Phoenix is asked if they favor the use of oxygenated fuels year-round to reduce air

Stells [14]

Answer:

a) 0.0853

b) 0.0000

Step-by-step explanation:

Parameters given stated that;

H₀ : p = 0.6

H₁ : p = 0.6, this explains the acceptance region as;

p° ≤ $\frac{315}{500}$ =0.63 and the region region as p°>0.63 (where p° is known as the sample proportion)

a).

the probability of type I error if exactly 60% is calculated as :

∝ = P (Reject H₀ | H₀ is true)

= P (p°>0.63 | p=0.6)

where p° is represented as pI in the subsequent calculated steps below

= P $[\frac{p°-p}{\sqrt{\frac{p(1-p)}{n}}} >\frac{0.63-p}{\sqrt{\frac{p(1-p)}{n}}} |p=0.6]$

= P $[\frac{p°-0.6}{\sqrt{\frac{0.6(1-0.6)}{500}}} >\frac{0.63-0.6}{\sqrt{\frac{0.6(1-0.6)}{500}}} ]$

= P $[Z>\frac{0.63-0.6}{\sqrt{\frac{0.6(1-0.6)}{500} } } ]$

= P [Z > 1.37]

= 1 - P [Z ≤ 1.37]

= 1 - Ф (1.37)

= 1 - 0.914657 ( from Cumulative Standard Normal Distribution Table)

≅ 0.0853

The probability of Type II error β is stated as:

β = P (Accept H₀ | H₁ is true)

= P [p° ≤ 0.63 | p = 0.75]

where p° is represented as pI in the subsequent calculated steps below

= P $[\frac{p°-p} \sqrt{\frac{p(1-p)}{n} } }\leq \frac{0.63-p}{\sqrt{\frac{p(1-p)}{n} } } | p=0.75]$

= P $[\frac{p°-0.6} \sqrt{\frac{0.75(1-0.75)}{500} } }\leq \frac{0.63-0.75}{\sqrt{\frac{0.75(1-0.75)}{500} } } ]$

= P $[Z\leq\frac{0.63-0.75}{\sqrt{\frac{0.75(1-0.75)}{500} } } ]$

= P [Z ≤ -6.20]

= Ф (-6.20)

≅ 0.0000 (from Cumulative Standard Normal Distribution Table).

6 0

3 years ago

Out of the last 50 guests, only one of them break coupon for free admission to the carnival. if there are 1500 guests expected t

ryzh [129]

1/50 = x/1500

Cross multiply:

50x = 1500(1)
50x = 1500
x = 1500/50
x = 30 people

Therefore, the answer is b as 30 people will receive free admissions.

6 0

3 years ago

One hundred students were asked to report their gender and their favorite school lunch: hamburger or pizza. The results are belo

jolli1 [7]

Step-by-step explanation:

Ok, so we have a total of 100 students being asked what they like more, Hamburgers or Pizza.

Out of the 40 males, 16 said hamburgers. The other 24 replied with Pizza

Out of the 60 females, 42 said hamburgers. The other 18 replied with Pizza.

The percent of females that preferred pizza is 18%

The percent of students that preferred hamburger is 58%

Hope this Helps!!

6 0

2 years ago