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▹ Answer
<em>D. 3x² + 13x - 56</em>
▹ Step-by-Step Explanation
(x + 7)(3x - 8) (<em>Using FOIL method)</em>
x * 3x - 8x + 7 * 3x - 7 * 8
3x² - 8x + 7 * 3x - 7 * 8
3x² - 8x + 21x - 56
3x² + 13x - 56
Hope this helps!
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Brainliest is greatly appreciated!
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According to HL theorem if one leg and hypotenuse of one right triangle are equal to one leg and hypotenuse of other right triangle, then the triangles are congruent.
By using this theorem we can set up the system of equations as follows:
x=y+1 ...(1)
2x+3= 3y + 3 ..(2)
By using equation (1) next step is to plug in y+1 for x in equation (2). So,
2 ( y + 1) + 3 = 3y + 3
2y + 2 + 3 = 3y + 3 By using distribution property.
2y + 5 = 3y + 3
2y + 5 - 5 = 3y + 3 - 5 Subtract 5 from each side.
2y = 3y - 2
2y - 3y = -2 Subtract 3y from each sides.
-y = -2
So, y=2
Next step is to plug in y=2 in equation (1) to get the value of x. Hence,
x= 2+1
=3
So, x=3 and y=2 make these triangles congruent.
So, the correct choice is 3. x = 3, y = 2.
The expression 3P2 can also be read as "permutation of 3 taken 2". This represents the number of ways in which the 3 items are arranged with the emphasis on the arrangement of the first two other items.
Answer:
Step-by-step explanation:
Okay so I will explain the first one.
2 to the power of 4 = 2x2x2x2
2 to the power of 6 = 2x2x2x2x2x2
2 to the power of 4 = 2x2x2x2
2^4 = 16
2^6 = 64
When you are multiplying powers you add.
+
When you subtract you takeaway.
-
So you would do
4+6+4
= 14
Meaning 2 to the power of 14
2
So what is 2 to the power of 14.
You would do
2x2x2x2x2x2x2x2x2x2x2x2x2x2
The answer is 16384
You can also use a calculator
GOOD LUCK FOR YOUR TEST!
El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.
<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>
La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.
Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:
σ = W / (π · D² / 4)
Donde:
- W - Peso de la caja, en newtons.
- D - Diámetro del área transversal de la caja, en metros.
Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:
σ = 25 N / [π · (0.02 m)² / 4]
σ ≈ 79577.472 Pa
<h3>Observación</h3>
La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.
Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145
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