Find four consecutive even integers such that if the sum of the first and the third is multiplied by 5 the result is 12 less tha
1 answer:
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Answer:
Step-by-step explanation:
Let's apply the formula (x+y)² = x² + 2xy + y²
Here, x = -a and y = b
So,
= (-a)² + 2(-a)(b) + (b)²
= a² - 2ab + b²
Hence, it has been proved that (-a + b)² = a² - 2ab + b².
Hope this helped!
<h3>~AH1807</h3>