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Vlad1618 [11]
2 years ago
13

Find four consecutive even integers such that if the sum of the first and the third is multiplied by 5 the result is 12 less tha

n 9 times the fourth
Mathematics
1 answer:
Fofino [41]2 years ago
6 0
4 consecutive even integers....x, x + 2, x + 4, x + 6

5(x + x + 4) = 9(x + 6) - 12
5(2x + 4) = 9x + 54 - 12
10x + 20 = 9x + 42
10x - 9x = 42 - 20
x = 22

x + 2 = 22 + 2 = 24
x + 4 = 22 + 4 = 26
x + 6 = 22 + 6 = 28

so ur numbers are : 22,24,26, and 28
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Please help with this question, thank you
Semmy [17]
Remark
The key step is just to subtract 5 from both sides. The pointed of the inequality still points away from the variable and towards the number. As long as that remains true, the correct answer can be found.

Solution
2.7 ≤ b + 5  Subtract 5 from both sides.
2.7 - 5 ≤ b
- 2.3 ≤ b      Write with the variable on the left.
b ≥ - 2.3  <<<< answer  
6 0
3 years ago
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If 6:2=8:x, then<br> a. 6x=16<br> b. 6x=10<br> c.2x=48<br> d. 2x=14
otez555 [7]

Answer:

a)6x = 16

Step-by-step explanation:

<h2><u>Finding the value</u></h2>

the ratio can be solved by <u>cross multiplication :</u>

6       :          2

8       :          x

6*x = 8*2

6x = 16

answer is : <u>a) 6x = 16</u>

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Preston is making cookies. He has fraction 4 over 5 cups of flour in a bag. He then used two fractions 1 over 10 cup scoops of f
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Step 2: 4/5 - 2/10
GCF: multiply both sides of 4/5 by 2 = 8/10

Step 3: 8/10 - 2-10 = 6/10

ANSWER: C <span>fraction 6 over 10, because fraction 4 over 5 minus 2 times fraction 1 over 10 equals fraction 4 over 5 minus fraction 2 over 10 </span>
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