Consider randomly selecting a student at a large university. Let A be the event that the selected student has a Visa card, let B
be the analogous event for MasterCard, and let C be the event that the selected student has an American Express card. Suppose that P(A) = 0.6, P(B) = 0.4, and P(A ? B) = 0.3, suppose that P(C) = 0.2, P(A ? C) = 0.11, P(B ? C) = 0.1, and P(A ? B ? C) = 0.07.
(a) What is the probability that the selected student has at least one of the three types of cards?
(b) What is the probability that the selected student has both a Visa card and a MasterCard but not an American Express card?
(c) Calculate P(B | A) and P(A | B).
P(B | A) =
P(A | B) =
(d) Interpret P(B | A) and P(A | B). (Select all that apply.)
P(A | B) is the probability that a student does not have a MasterCard or a Visa card.
P(B | A) is the probability that given that a student has a Visa card, they also have a MasterCard.
P(A | B) is the probability that given that a student has a Visa card, they also have a MasterCard.
P(B | A) is the probability that given that a student has a MasterCard, they also have a Visa card.
P(B | A) is the probability that a student does not have a MasterCard or a Visa card.
P(A | B) is the probability that given that a student has a MasterCard, they also have a Visa card.
(e) If we learn that the selected student has an American Express card, what is the probability that she or he also has both a Visa card and a MasterCard?
(f) Given that the selected student has an American Express card, what is the probability that she or he has at least one of the other two types of cards?
OK so you point is y=4 and x=3 so plot that on a x,y graph. Then to turn it -270 degrees you need to clock wise. normally you would just go counter clock wise but since your rotation is negative you go counter clock wise. hope this helped!!
-5.55-8.55c+4.35c 2nd and 3rd term is like term we can connect. -digit have to larger number than +digit so the sign will be negative -5.55-4.2c there is no like term to connect Hence this is the answer
Two triangles of different sizes make up the logo. We are to find the difference in the areas of these triangle. Smaller triangle has a base of 2 cm and height 6 cm. Larger triangle has the base of 3 cm and height 7 cm.
Area of the triangle = x Base x Height
So, Area of smaller triangle = cm² Area of larger triangle = cm²
The difference in the areas of triangles = 10.5 - 6 = 4.5 cm²<span />
x Base x Height
cm²
cm²