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lawyer [7]
3 years ago
12

jacob bought 5 pencils for 80 cents. At this same rate, how many pencils can hee but for 40 cents? Explain why this answer does

not make sense
Mathematics
1 answer:
Step2247 [10]3 years ago
3 0
5 pencils cost $.80. Each pencil costs $0.16
Then divide $0.16 into $0.40
This equals 2.5 pencils, you can't buy half a pencil
You might be interested in
Which linear function represents the line given by the point-slope equation y – 2 = 4(x – 3)?
patriot [66]

y = 4x - 10. The linear functions y = 4x - 10 represent the line given by the point-slope equation y - 2 = 4(x - 3).

In order to solve this problem, we have to take the point-slope equation y - 2 = 4(x - 3) and convert it to the linear function form y = mx + b as follow:

y - 2 = 4(x - 3)

y - 2 = 4(x) - (4)(3)

y - 2 = 4x - 12

y - 2 + 2 = 4x -12 +2

y = 4x - 10 (Linear function)

8 0
3 years ago
What is the value of the expression 2 over 3 subtracted by 5 over 6 divided by 3 over 4
Tju [1.3M]
I did the problem and I got negative 4 over 9
5 0
3 years ago
Read 2 more answers
In parallelogram ABCD, AD = 4x - 10 and BC = 3x + 2. Find AD.
Helga [31]

Answer:12


Step-by-step explanation:

4x - 10= 3x+2 add 10= 4x = 3x+12 subtract 3x=1x 1x=12 divide 12 by 1=12 should be 12 sorry if I got it wrong...

8 0
4 years ago
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 144 millimeters,
valentinak56 [21]

Answer:

The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample  means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean  is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

<em>μ</em> = 144 mm

<em>σ</em> = 7 mm

<em>n</em> = 50.

Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

\bar X\sim N(\mu_{\bar x}=144, \sigma_{\bar x}^{2}=0.98)

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:

P(\bar X-\mu_{\bar x}>2.6)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}} >\frac{2.6}{\sqrt{0.98}})

                           =P(Z>2.63)\\=1-P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

8 0
3 years ago
Simplify 2m - [n - (m - 2n)]. -3m - n 3m - n -3m - 3n 3m - 3n
zhenek [66]

Answer:

3m-3n

Step-by-step explanation:

We want to simplify the expression;

2m - [n - (m - 2n)].

We expand the parenthesis to obtain;

2m - (n - m + 2n)

2m - ( - m + 3n)

Expand further to get;

2m +m -3n

Combine the first two terms;

3m-3n

4 0
4 years ago
Read 2 more answers
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