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Firlakuza [10]
4 years ago
14

Henrietta interviewed her classmates on their favorite subjects. She recorded their gender and favorite subject. She concluded t

hat males felt about math the way that females felt about science. Is she correct?
Mathematics
2 answers:
qwelly [4]4 years ago
8 0

D) no, the relative frequency of males who like math is different from the relative frequency of females who like science.

Tamiku [17]4 years ago
4 0
<span>no, the relative frequency of males who like math is different from the relative frequency of females who like science.</span>
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P= $16,000, r= 10%, t= 180 days<br> Assume 360 days in a year.
labwork [276]
Interest = (principal)(rate as a decimal)(time in years)

I = (16,000)(0.1)(0.5)
I = $800
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3 years ago
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Jacob wants to buy a $500,000 15-year term life policy, and the annual premium rate (per $1000 of face value) for his age group
kykrilka [37]

If Jacob lives until the end of the term of his policy, the total amount he would have paid in premiums overall is $50,850.

<h3>How much would he have paid in premiums?</h3>

Total premium payment = (face value / average premium rate) x number of years x premium

($500,000 / 1000) x $6.78 x 15 = $50,850

To learn more about division, please check: brainly.com/question/194007

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2 years ago
I USED ALL MY POINTS! PLEASE HELP ME ASAP!!!
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Answer:

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Step-by-step explanation:

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3 years ago
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In a sample of nequals16 lichen​ specimens, the researchers found the mean and standard deviation of the amount of the radioacti
GuDViN [60]

Answer:

(a) The confidence level desired by the researchers is 95%.

(b) The sampling error is 0.002 microcurie per millilitre.

(c) The sample size necessary to obtain the desired estimate is 25.

Step-by-step explanation:

The mean and standard deviation of the amount of the radioactive​ element, cesium-137 present in a sample of <em>n</em> = 16 lichen specimen are:

\bar x=0.009\\s=0.005

Now it is provided that the researchers want to increase the sample size in order to estimate the mean μ to within 0.002 microcurie per millilitre of its true​ value, using a​ 95% confidence interval.

The (1 - <em>α</em>)% confidence interval for population mean (μ) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{s}{\sqrt{n}}

(a)

The confidence level is the probability that a particular value of the parameter under study falls within a specific interval of values.

In this case the researches wants to estimate the mean using the 95% confidence interval.

Thus, the confidence level desired by the researchers is 95%.

(b)

In case of statistical analysis, during the computation of a certain statistic, to estimate the value of the parameter under study, certain error occurs which are known as the sampling error.

In case of the estimate of parameter using a confidence interval the sampling error is known as the margin of error.

In this case the margin of error is 0.002 microcurie per millilitre.

(c)

The margin of error is computed using the formula:

MOE=z_{\alpha/2}\times \frac{s}{\sqrt{n}}

The critical value of <em>z</em> for 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a <em>z</em>-table.

MOE=z_{\alpha/2}\times \frac{s}{\sqrt{n}}

 0.002=1.96\times \frac{0.005}{\sqrt{n}}

       n=[\frac{1.96\times 0.005}{0.002}]^{2}

          =(4.9)^{2}\\=24.01\\\approx 25

Thus, the sample size necessary to obtain the desired estimate is 25.

6 0
4 years ago
What is the slope of these two points (2,-6) and (5,-12
Blizzard [7]

Step-by-step explanation:

slope= <u>y</u><u>²</u><u>-</u><u>y</u><u>¹</u>

x²-x¹

<u>-12--6</u>

5-2

-12+6

6 0
3 years ago
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