Answer:
b. 0.94 i think is the answer
Answer:
41.2 m.
Explanation:
It takes half the time that is (5.8/2) = 2.9 seconds, for the ball to reach its apex.
Given:
S = 83 m
t = 5.8 s
vf = 0 m/s
a = - g
= - 9.81 m/s^2
Equations of motion:
i. vf = vi + a * t
ii. h = vi * t + 1/2 (a * t²)
Using the i. equation of motion:
0 m/s = vi - (9.8 m/s²) (2.9 sec)
vi = 28.4 m/s.
Using the ii. equation of motion:
h = (28.4 * 2.9 ) - 1/2 (9.8 * (2.9)²)
= 82.4 - 41.2
= 41.2 m.
Answer:
A = 0.325 Bq
Explanation:
given,
half life of ¹⁴C = 5730 years
fixed fraction 1.30 × 10⁻¹² of ¹²C
half life = 5730 years
T_{1/2} = 5730 x 365 x 24 x 60 x 60
= 1.807 x 10¹¹ s
radioactive decay constant
λ =
λ =
λ = 3.835 x 10⁻¹² /s
number of atom
mass m = 1.30 g
n = 6.524 x 10²²
Number of ¹⁴C atoms in 1.3 g of sample N ' =
= 1.30 × 10⁻¹² x 6.524 x 10²²
= 8.482 x 10¹⁰
Required activity, A = λ N
A = 3.835 x 10⁻¹² x 8.482 x 10¹⁰
A = 0.325 Bq