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Anna11 [10]
3 years ago
9

A pitcher throws a 0.14-kg baseball toward the batter so that it crosses home plate horizontally and has a speed of 42 m/s just

before it makes contact with the bat. The batter then hits the ball straight back at the pitcher with a speed of 48 m/s. Assume the ball travels along the same line leaving the bat as it followed before contacting the bat. a. What is the magnitude of the impulse delivered by the bat to the baseball? b. If the ball is in contact with the bat for 0.0050 s, what is the magnitude of the average force exerted by the bat on the ball?
Physics
1 answer:
kykrilka [37]3 years ago
5 0

Answer

given,

mass of base ball = 0.14 kg

speed before it made the contact with the ball (V i) = 42 m/s

speed after batter hit the ball(V f) = - 48 m/s

a)                                            

impulse = change in momentum

             = m\times (V_f-V_i)      

             =0.14\times (-48-42)

             = -12.6 Kg m/s

Magnitude of impulse = 12.6 Kg m/s

b)                                                        

Force = \dfrac{impulse}{time}

          =  \dfrac{12.6}{0.005}

Force = 2520 N

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Answer:

f=5.76\times 10^{14}\ Hz

Explanation:

We need to find the frequency of green light having wavelength o5.2\times 10^{-7}\ m. It can be calculated as follows :

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So, the required frequency of green light is equal to 5.76\times 10^{14}\ Hz.

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A 20-gram bullet traveling at 250 m/s strikes a block of wood that weighs 2 kg. With what velocity will the block and bullet mov
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Answer:

the velocity of the bullet-wood system after the collision is 2.48 m/s

Explanation:

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mass of the wood, m₁ = 2 kg

velocity of the wood, v₁ = 0

Let the velocity of the bullet-wood system after collision = v

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Initial momentum = final momentum

m₀v₀ + m₁v₁ = v(m₀ + m₁)

0.02 x 250  + 2 x 0    =    v(2  + 0.02)

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v = 5/2.02

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The work done by the three students is 3,000 J.

The energy transferred in the process is 3,000 J.

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The work done by the three students is calculated as follows;

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W = 3,000 J

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The energy transferred in the process is determined by work energy theorem.

E = W

E = 3,000 J

Learn more about work-energy theorem here: brainly.com/question/22236101

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