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Anna11 [10]
3 years ago
9

A pitcher throws a 0.14-kg baseball toward the batter so that it crosses home plate horizontally and has a speed of 42 m/s just

before it makes contact with the bat. The batter then hits the ball straight back at the pitcher with a speed of 48 m/s. Assume the ball travels along the same line leaving the bat as it followed before contacting the bat. a. What is the magnitude of the impulse delivered by the bat to the baseball? b. If the ball is in contact with the bat for 0.0050 s, what is the magnitude of the average force exerted by the bat on the ball?
Physics
1 answer:
kykrilka [37]3 years ago
5 0

Answer

given,

mass of base ball = 0.14 kg

speed before it made the contact with the ball (V i) = 42 m/s

speed after batter hit the ball(V f) = - 48 m/s

a)                                            

impulse = change in momentum

             = m\times (V_f-V_i)      

             =0.14\times (-48-42)

             = -12.6 Kg m/s

Magnitude of impulse = 12.6 Kg m/s

b)                                                        

Force = \dfrac{impulse}{time}

          =  \dfrac{12.6}{0.005}

Force = 2520 N

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When you hit a ball with baseball bat, the bat exerts a great force on the ball which causes the ball to accelerate in the opposite direction. It is to be noted that the mass of bat is much greater than mass of ball but the acceleration of ball is also greater than the acceleration of the bat so both bat and ball almost exert same magnitude of force but in opposite direction and as a result both bat and ball accelerate in opposite direction, the deciding factor is of course the relative force applied by the batter and the bowler.

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Alja [10]
<h2>Answer</h2>

option D)

2.4 seconds

<h2>Explanation</h2>

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Force to due frictional force in reverse direction

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<h2>-mg(friction coefficient) = ma  </h2>

(cancelling mass from both side of equation)

g(0.8) = a

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adoni [48]

The energy stored in a capacitor is

E = (1/2) · (capacitance) · (voltage)²

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<em>E = 4.32 x 10⁻⁴ Joule</em>

(That's 0.000432 of a Joule)

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