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BigorU [14]
3 years ago
7

A 32 kg child puts a 15 kg box into a 12 kg wagon. The child then pulls horizontally on the wagon with a force of 65 N. if the b

ox does not move relative to the wagon, what is the static friction force on the box?
A 32 kg child puts a 15 kg box into a 12 kg wagon. The child then pulls horizontally on the wagon with a force of 65 N. if the box does not move relative to the wagon, what is the static friction force on the box?
Physics
1 answer:
snow_tiger [21]3 years ago
6 0
150/gen add 55to it then it is 5689
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Why do the lighter isotopes disappear first from the atmosphere? Where do those isotopes go?
denpristay [2]

Lighter molecules move fast and escape from the upper atmosphere relatively quickly.

To find the answer, we have to know more about the lighter isotopes.

<h3>What are lighter isotopes?</h3>
  • Lighter molecules are mobile and soon leave the higher atmosphere.
  • A particular element's stable isotopes have slightly different atomic masses and quantum mechanical energies.
  • The lighter isotope of an element's chemical bonds are more easily broken than the heavier isotope's.
  • As a result, the light isotope typically benefits from chemical reactions.

Thus, we can conclude that, lighter molecules move fast and escape from the upper atmosphere relatively quickly.

Learn more about the isotopes here:

brainly.com/question/364529

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3 0
1 year ago
Por que no céu sem nuvens a lua nova não é visivel e a lua cheia aparece em grande destaque?
weeeeeb [17]
Porque la matematica es imposible

4 0
3 years ago
4. Two forces act on a 2 kg object as shown. What is the magnitude of the acceleration of the object?
aleksandrvk [35]

The resultant force on the object is

∑ <em>F</em> = 〈0, 8〉 N + 〈6, 0〉 N = 〈6, 8〉 N

which has a magnitude of

<em>F</em> = √((6 N)² + (8 N)²) = √(100 N²) = 10 N

By Newton's second law, the acceleration has magnitude <em>a</em> such that

<em>F</em> = <em>m a</em>

10 N = (2 kg) <em>a</em>

<em>a</em> = (10 N) / (2 kg)

<em>a</em> = 5 m/s²

so the answer is B.

4 0
3 years ago
An aerobatic airplane pilot experiences weightlessness as she passes over the top of a loop-the-loop maneuver. the acceleration
Yanka [14]
The acceleration due to gravity serves as the centripetal acceleration of the objects that orbits the Earth. The centripetal acceleration due to gravity is calculated through the equation,

    a = v²/r

where v is the speed and r is the radius. Substituting the known values to the equation,

   9.8 m/s² = (420 m/s)² / r

The value of r from the equation is 18000 m or equal to 18 km.

<em>Answer: 18 km</em>
6 0
3 years ago
A total charge of 4.70 is distributed on two metal spheres. When the spheres are 10 cm apart, they each feel a repulsive force o
Anna35 [415]

Answer:0.114 C

Explanation:

Given

Total 4.7 C is distributed in two spheres

Let q_1 and q_2 be the charges such that

q_1+q_2=4.7

and Force between charge particles is given by

F=\frac{kq_1q_2}{r^2}

4.7\times 10^11=\frac{9\times 10^9\times q_1\cdot q_2}{0.1^2}

q_1\cdot q_2=0.522

put the value of q_1

q_2\left ( 4.7-q_2\right )=0.522

q_2^2-4.7q_2+0.522=0

q_2=\frac{4.7\pm \sqrt{4.7^2-4\times 1\times 0.522}}{2}

q_2=0.114 C

thus q_1=4.586 C

3 0
3 years ago
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