Explanation:
Work = force × displacement
532 J = 48 N × d
d ≈ 11 m
Answer:
V = 0.0806 m/s
Explanation:
given data
mass quarterback = 80 kg
mass football = 0.43 kg
velocity = 15 m/s
solution
we consider here momentum conservation is in horizontal direction.
so that here no initial momentum of the quarterback
so that final momentum of the system will be 0
so we can say
M(quarterback) × V = m(football) × v (football) ........................1
put here value we get
80 × V = 0.43 × 15
V = 0.0806 m/s
Answer:
K =6.697 Kg/s²
Explanation:
Given:
delta m =41 g = 0.041 kg
delta x = 6cm = 0.06m
g = 9.8 m/s²
according to the given formula
K = delta m g /delta x
K = (0.041 kg × 9.8 m/s²) / 0.06m
K =6.697 Kg/s²
Explanation:
It is given that,
Speed of the jet airplane with respect to air, 
If the wind at the airliner’s cruise altitude is blowing at 100 km/h from west to east, 
(A) Let 
is the speed of the airliner relative to the ground if the airplane is flying from west to east,
(B) Let 
is the speed of the airliner relative to the ground if the airplane is flying from east to west,
Hence, this is the required solution.
