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Alik [6]
3 years ago
6

25 points!!!!!! PLEASE HELP UGHHHHHHHHHHHHHHHHHHHHHHHHHHH

Mathematics
1 answer:
Dovator [93]3 years ago
5 0
Because of the -2 at the end of the function, we know it is shifted down. The +1 means it is shifted left. The answer is the last graph (the one with a y-intercept of  -1).
You might be interested in
Graph the function y = 2x3 – x2 – 4x + 5. To the nearest tenth, over which interval is the function decreasing?
daser333 [38]
As you progress in math, it will become increasingly important that you know how to express exponentiation properly.

y = 2x3 – x2 – 4x + 5  should be written    <span>y = 2^x3 – x^2 – 4^x + 5.  The 
" ^ " symbol denotes exponentiation.

I see you're apparently in middle school.  Is that so?  If so, are you taking calculus already?  If so, nice!

Case 1:  You do not yet know calculus and have not differentiated or found critical values.  Sketch the function          </span>y = 2x^3 – x^2 – 4^x + 5, including the y-intercept at (0,5).  Can you identify the intervals on which the graph appears to be increasing and those on which it appears to be decreasing?

Case 2:  You do know differentiation, critical values and the first derivative test.  Differentiate  y = 2x^3 – x^2 – 4^x + 5 and set the derivative = to 0:

dy/dx = 6x^2 - 2x - 4 = 0.  Reduce this by dividing all terms by 2:

dy/dx = 3x^2 - x - 2 = 0    I used synthetic div. to determine that one root is x = 2/3.  Try it yourself.  This leaves the coefficients of the other factor, (3x+3); this other factor is x = 3/(-3) = -1.  Again, you should check this.

Now we have 2 roots:  -1 and 2/3

Draw a number line.  Locate the origin (0,0).  Plot the points (-1, 0) and (2/3, 0).  This subdivides the number line into 3 subintervals:

(-infinity, -1), (-1, 2/3) and (2/3, infinity).

Choose a test number from each interval and subst. it for x in the derivative formula above.  If the derivative comes out +, the function is increasing on that interval; if -, the function is decreasing.

Ask all the questions you want, if this explanation is not sufficiently clear.

4 0
3 years ago
Read 2 more answers
I need help :/ i have five questions
IrinaK [193]

Answer:


Step-by-step explanation:

1. The given equation is:

\frac{3}{5}{\times}\frac{4}{5}

Multiplying both the terms, we get

\frac{12}{25}

Option A is correct.

2. The given equation is:

2\frac{1}{3}{\times}\frac{3}{4}

Converting the improper fraction into the mixed fraction,

\frac{7}{3}{\times}\frac{3}{4}

=\frac{7}{4}

Option C is correct.

3. The given equation is:

\frac{3}{16}{\times}\frac{4}{21}

Multiplying both the terms, we get

=\frac{1}{28}

4. The given equation is:

3\frac{8}{9}{\times}4\frac{4}{5}

Converting the improper fraction into the mixed fraction,

\frac{35}{9}{\times}\frac{24}{5}

=\frac{56}{3}

5. One package contains= 5\frac{1}{4}=\frac{21}{4} pounds of raisins.

4\frac{2}{3} packages contains=4\frac{2}{3}{\times}5\frac{1}{4} pounds of raisins.

=\frac{14}{3}{\times}\frac{21}{4}

=\frac{49}{2}

Therefore, the baker used \frac{49}{2} pounds of raisins.

5 0
3 years ago
Express the system as AX = B; then solve using matrix inverses
Wittaler [7]

Answer with explanation:

1. The given equations are

3x -5 y=2

-x+2 y= 0

⇒The matrix in the form of , AX=B, is

A=\left[\begin{array}{cc}3&-5\\-1&2\end{array}\right] ,\\\\ X=\left[\begin{array}{c}x&y\end{array}\right],\\\\B=\left[\begin{array}{c}2&0\end{array}\right]

\rightarrow X=A^{-1}B\\\\\rightarrow X=\frac{Adj.A}{|A|}\times B

Adj.A=Transpose of cofactor of Matrix A

Adj.A=\left[\begin{array}{cc}2&1\\5&3\end{array}\right] ,\\\\ |A|=6-5\\\\|A|=1\\\\\left[\begin{array}{c}x&y\end{array}\right]=\left[\begin{array}{cc}2&5\\1&3\end{array}\right] \times \left[\begin{array}{c}2&0\end{array}\right]\\\\x=4, y=2

2.

The given equations are

x+y-z=2

x+z=7

2 x +y+z=13

⇒The matrix in the form of , AX=B, is

   A=\left[\begin{array}{ccc}1&1&-1\\1&0&1\\2&1&1\end{array}\right]\\\\ X=\left[\begin{array}{ccc}x\\y\\z\end{array}\right]\\\\B= \left[\begin{array}{ccc}2\\7\\13\end{array}\right]\\\\\rightarrow X=A^{-1}B\\\\\rightarrow X=\frac{Adj.A}{|A|}\times B\\\\a_{11}=-1,a_{12}=1,a_{13}=1,a_{21}=-2,a_{22}=3,a_{23}=1,a_{31}=1,a_{32}=-2,a_{33}=-1\\\\|A|=1\times(0-1)-1\times(1-2)-1\times(1-0)\\\\=-1+1-1\\\\|A|=-1\\\\Adj.A=\left[\begin{array}{ccc}-1&-2&1\\1&3&-2\\1&1&-1\end{array}\right]

\frac{Adj.A}{|A|}=\left[\begin{array}{ccc}1&2&-1\\-1&-3&2\\-1&-1&1\end{array}\right]\\\\X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}1&2&-1\\-1&-3&2\\-1&-1&1\end{array}\right]\times\left[\begin{array}{ccc}2\\7\\13\end{array}\right]\\\\x=3,y=3,z=4

7 0
3 years ago
Find the slope of the line that contains the points (-5, 3) and (-1,-5).<br>​
Nutka1998 [239]

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em>

8 0
2 years ago
HELP ASAP PLEASE :))))))
IrinaK [193]

Answer:

7

Step-by-step explanation:

because I am smart and cause im smart

5 0
3 years ago
Read 2 more answers
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