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Travka [436]
3 years ago
12

When dividing the polynomial p (1) = 4t^3 - 17t^2+ 14t - 3 by t - 3, the remainder can be determined by evaluating p(3). What is

the value of this
remainder?
A P(3) = -27
B. P(3) = -6
C. P(3) = 0
D. p(3) = 45
Mathematics
1 answer:
Brut [27]3 years ago
3 0

Answer:

The answer to your question is the letter B. P(3) = -6

Step-by-step explanation:

                                     4t²- 5t -1

                           t - 3   4t³ - 17t² + 14t - 3

                                   -4t³  +12t²

                                     0    -5t² +14t

                                           +5t² -15t

                                             0    - t   - 3

                                                   +t   -3

                                                     0   -6

Quotient = 4t² - 5t - 1

Remainder = -6

The remainder is constant it always be -6

P(3) = 4(3)³ - 17(3)² + 14(3) - 3

       = 4(27) - 17(9) + 42 - 3

       = 108 - 153 + 42 - 3

       = 150 - 156

      = -6

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In this question, p q r is a prime number. Most of the prime number is an odd number. If p q r all odd number, it wouldn't be possible to get 73 since
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Since 73 is an odd number, it is clear that one of the p q r needs to be an even number. 

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