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Travka [436]
3 years ago
12

When dividing the polynomial p (1) = 4t^3 - 17t^2+ 14t - 3 by t - 3, the remainder can be determined by evaluating p(3). What is

the value of this
remainder?
A P(3) = -27
B. P(3) = -6
C. P(3) = 0
D. p(3) = 45
Mathematics
1 answer:
Brut [27]3 years ago
3 0

Answer:

The answer to your question is the letter B. P(3) = -6

Step-by-step explanation:

                                     4t²- 5t -1

                           t - 3   4t³ - 17t² + 14t - 3

                                   -4t³  +12t²

                                     0    -5t² +14t

                                           +5t² -15t

                                             0    - t   - 3

                                                   +t   -3

                                                     0   -6

Quotient = 4t² - 5t - 1

Remainder = -6

The remainder is constant it always be -6

P(3) = 4(3)³ - 17(3)² + 14(3) - 3

       = 4(27) - 17(9) + 42 - 3

       = 108 - 153 + 42 - 3

       = 150 - 156

      = -6

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Write 5600 in standard form
Mrac [35]

Answer:

5.6 x 10^3 (10 to the power of 3)

i.e. 5600 = 5.6 x 10^3 because you have to go back 3 times to get 5.6 *you cannot have a number less than 1 or more than 10*

So the power of 3 is the amount of times you had to move back

Step-by-step explanation:

This is how you write 5600 in standard form!

HOPE THIS HELPS!!

3 0
3 years ago
Read 2 more answers
Calculate the measure of arc AC if the measure of arc CD is 170 degrees and arc AB is 80 and AB||CD.
CaHeK987 [17]

Answer:

  AC = 55°

Step-by-step explanation:

In this geometry, arcs AC and BD have the same measure. The sum of the parts of arc CD will total the measure of CD.

  AC + AB + BD = CD

  2AC +80 = 170

  AC = 110/2 = 55

The measure of arc AC is 55°.

5 0
2 years ago
A product can be made in sizes huge, average and tiny which yield a net unit profit of $14, $10, and$5, respectively. Three cent
navik [9.2K]

Answer:

The model is:

z = 14* X₁₁ + 14*X₁₂ + 5*X₁₃ + 10*X₂₁ + 10*X₂₂ + 10*X₂₃ + 5*X₃₁ + 5*X₃₂ + 5*X₃₃    to maximize

Subject to:

First center               X₁₁  +  X₂₁  + X₃₁  ≤  550

Second center         X₁₂  +  X₂₂  + X₃₂  ≤ 750

Third center               X₁₃  + X₂₃  + X₃₃  ≤ 275                  

22* X₁₁  + 16* X₂₁  + 9*X₃₁     ≤   11000

22* X₁₂  + 16* X₂₂  + 9*X₃₂   ≤   2700

22*X₁₃  + 16* X₂₃  +  9*X₃₃  ≤  3400

X₁₁  +  X₁₂  + X₁₃  ≤  710

X₂₁  + X₂₂ + X₂₃  ≤  900

X₃₁ + X₃₂ + X₃₃  ≤  350

2700*(X₁₁  +  X ₂₁  + X₃₁)  -  11000*(X₁₂ + X₂₂ + X₃₂) = 0

3400*(X₁₁  +  X ₂₁  + X₃₁) - 11000*( ( X₁₃ + X₂₃ + X₃₃) = 0

Xij >= 0

Step-by-step explanation:

Let´s call Xij   product size i produced in center j

According to this, we get the following set of variable

X₁₁    product size huge produced in center 1

X₁₂    product size huge produced in center 2

X₁₃   product size huge produced in center 3

X₂₁   product size average produced in center 1

X₂₂   product size average produced in center 2

X₂₃   product size average produced in center 3

X₃₁  product size-tiny produced in center 1

X₃₂ product size-tiny produced in center 2

X₃₃ product size-tiny produced in center 3

Then Objective function is

z = 14* X₁₁ + 14*X₁₂ + 5*X₁₃ + 10*X₂₁ + 10*X₂₂ + 10*X₂₃ + 5*X₃₁ + 5*X₃₂ + 5*X₃₃

Constrains

Center capacity

1.-   First center               X₁₁  +  X₂₁  + X₃₁  ≤  550

2.-   Second center         X₁₂  +  X₂₂  + X₃₂  ≤ 750

3.- Third center               X₁₃  + X₂₃  + X₃₃  ≤ 275

Water available

1.-  22* X₁₁  + 16* X₂₁  + 9*X₃₁     ≤   11000

2.-  22* X₁₂  + 16* X₂₂  + 9*X₃₂   ≤   2700

3.-   22*X₁₃  + 16* X₂₃  +  9*X₃₃  ≤  3400

Demand constrain

Product huge

X₁₁  +  X₁₂  + X₁₃  ≤  710

Product average

X₂₁  + X₂₂ + X₂₃  ≤  900

Product tiny

X₃₁ + X₃₂ + X₃₃  ≤  350

Fraction SP/CC must be the same

First and second centers  fraction SP/CC  

(X₁₁  +  X ₂₁  + X₃₁)/ 11000   =  (X₁₂ + X₂₂ + X₃₂)/ 2700

2700*(X₁₁  +  X ₂₁  + X₃₁)  -  11000*(X₁₂ + X₂₂ + X₃₂) = 0

First and third centers  fraction SP/CC  

(X₁₁  +  X ₂₁  + X₃₁)/ 11000   = ( X₁₃ + X₂₃ + X₃₃)/ 3400

3400*(X₁₁  +  X ₂₁  + X₃₁) - 11000*( ( X₁₃ + X₂₃ + X₃₃) = 0

The model is:

z = 14* X₁₁ + 14*X₁₂ + 5*X₁₃ + 10*X₂₁ + 10*X₂₂ + 10*X₂₃ + 5*X₃₁ + 5*X₃₂ + 5*X₃₃

Subject to:

First center               X₁₁  +  X₂₁  + X₃₁  ≤  550

Second center         X₁₂  +  X₂₂  + X₃₂  ≤ 750

Third center               X₁₃  + X₂₃  + X₃₃  ≤ 275                  

22* X₁₁  + 16* X₂₁  + 9*X₃₁     ≤   11000

22* X₁₂  + 16* X₂₂  + 9*X₃₂   ≤   2700

22*X₁₃  + 16* X₂₃  +  9*X₃₃  ≤  3400

X₁₁  +  X₁₂  + X₁₃  ≤  710

X₂₁  + X₂₂ + X₂₃  ≤  900

X₃₁ + X₃₂ + X₃₃  ≤  350

2700*(X₁₁  +  X ₂₁  + X₃₁)  -  11000*(X₁₂ + X₂₂ + X₃₂) = 0

3400*(X₁₁  +  X ₂₁  + X₃₁) - 11000*( ( X₁₃ + X₂₃ + X₃₃) = 0

Xij >= 0

6 0
2 years ago
What is 4 3/10 plus (-6.2) in decimal form
k0ka [10]

Answer:

Step-by-step explanation:

First change 4 3/10 to 4.3. Then you change 4.3 + -6.2 to 4.3 - 6.2.

Then you do 4.3 - 6.2 and you should get - 1.9.

5 0
3 years ago
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On his first day of school, Kareem found the high temperature in degrees Fahrenheit to be 76.1°. He plans to use the function to
wolverine [178]
The function for conversions from Fahrenheit to Celsius is:

Celsius = (Fahrenheit - 32) x 5/9 

C(76.1) = (76.1 - 32) x 5/9
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Therefore, 76.1 degrees Fahrenheit = 24.5 degrees Celsius. 
5 0
3 years ago
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