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3 years ago

A student writes 5y times 3 to model the relationship "the sum of 5y and 3" explain the ero

Mathematics

1 answer:

nydimaria [60]3 years ago

7 0

The student wrote the wrong operation. "The sum of 5y and 3" translates to 5y+3. And here means addition.

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Right triangle FGH has midsegments of 15,36, and 39 centimeters given that area of a triangle is represented by the formula A=1/

Schach [20]

Answer:

Step-by-step explanation:

according to the midsegment theorem, a midsegment of a triangle is parallel to a side of a triangle and its length is 1/2 length of the side.

1/2FG= 15, SO FG=30,

1/2 GH=36 SO GH=72

AREA = 1/2(72*30)=1080 CM^2

3 0

2 years ago

Read 2 more answers

Which number can each term of the equation be multiplied by to eliminate the fractions before solving? -3/4m-1/2=2+1/4m

Wittaler [7]

Answer:

* 2/3 / formula then multiply the numbers then you get the answer

6 0

2 years ago

So the question on the pic

gtnhenbr [62]

Explanation + answers

Because there are lengths going from 0 to 1, the lines must mean either decimals or fractions (we'll use fractions for this.)

1. There are twelve lines from 0 and 1, which we can use as the denominator for our fraction. This means the length of each line is 1/12.

2. In order to find where K's point is at, we simply need to count until we get to it. After counting, I see that K is on point 8/12, which we can simplify to get a smaller number. If we simplify once, we get 4/6, which we can again simplify to get 2/3. This gives us the answer K is on point 8/12 or 2/3.

4 0

2 years ago

TO TRANSMIT INFORMATION ON THE INTERNET, LARGE FILES ARE BROKEN INTO PACKETS OF SMALLER SIZES. EACH PACKET HAS 1,500 BYTES OF IN

stich3 [128]

Answer:

A. It would be needed 20 packets to transmit 30,000 bytes of information and B. 45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.

Step-by-step explanation:

1. Let's review the information provided to us for solving the question:

Size of each packet of information = 1,500 bytes

Number of packets = P

Number of bytes of information = B

2. Let's answer the questions:

A. How many packets would be needed to transmit 30,000 bytes of information?

P = 30,000 ÷ 1,500

P = 20

It would be needed 20 packets to transmit 30,000 bytes of information

B. How much information could be transmitted in 30,000 packets?

B = 30,000 * 1,500

B = 45'000,000

45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.

Note: Same answer provided to question 14037480, answered by me.

7 0

2 years ago

The sum of two numbers is 21. The larger number is 6 less than twice the smaller number. Find the two numbers.

Vesnalui [34]

Hey there! :D

21= 2x-6+x

21=3x-6

27=3x

x=9

The smaller number is 9.

The larger number is:

9*2= 18 18-6= 12

The larger number is 12.

I hope this helps!
~kaikers

3 0

2 years ago