25.20, that might help you hopefully!
In order to determine whether the equations are parallel, perpendicular, or neither, let's simply each equation into a slope-intercept form or basically, solve for y.
Let's start with the first equation.
![\frac{6x-5y}{2}=x+1](https://tex.z-dn.net/?f=%5Cfrac%7B6x-5y%7D%7B2%7D%3Dx%2B1)
Cross multiply both sides of the equation.
![6x-5y=2(x+1)](https://tex.z-dn.net/?f=6x-5y%3D2%28x%2B1%29)
![6x-5y=2x+2](https://tex.z-dn.net/?f=6x-5y%3D2x%2B2)
Subtract 6x on both sides of the equation.
![6x-5y-6x=2x+2-6x](https://tex.z-dn.net/?f=6x-5y-6x%3D2x%2B2-6x)
![-5y=-4x+2](https://tex.z-dn.net/?f=-5y%3D-4x%2B2)
Divide both sides of the equation by -5.
![-\frac{5y}{-5}=\frac{-4x}{-5}+\frac{2}{-5}](https://tex.z-dn.net/?f=-%5Cfrac%7B5y%7D%7B-5%7D%3D%5Cfrac%7B-4x%7D%7B-5%7D%2B%5Cfrac%7B2%7D%7B-5%7D)
![y=\frac{4}{5}x-\frac{2}{5}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B4%7D%7B5%7Dx-%5Cfrac%7B2%7D%7B5%7D)
Therefore, the slope of the first equation is 4/5.
Let's now simplify the second equation.
![-4y-x=4x+5](https://tex.z-dn.net/?f=-4y-x%3D4x%2B5)
Add x on both sides of the equation.
![-4y-x+x=4x+5+x](https://tex.z-dn.net/?f=-4y-x%2Bx%3D4x%2B5%2Bx)
![-4y=5x+5](https://tex.z-dn.net/?f=-4y%3D5x%2B5)
Divide both sides of the equation by -4.
![\frac{-4y}{-4}=\frac{5x}{-4}+\frac{5}{-4}](https://tex.z-dn.net/?f=%5Cfrac%7B-4y%7D%7B-4%7D%3D%5Cfrac%7B5x%7D%7B-4%7D%2B%5Cfrac%7B5%7D%7B-4%7D)
![y=-\frac{5}{4}x-\frac{5}{4}](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B5%7D%7B4%7Dx-%5Cfrac%7B5%7D%7B4%7D)
Therefore, the slope of the second equation is -5/4.
Since the slope of each equation is the negative reciprocal of each other, then the graph of the two equations is perpendicular to each other.
Answer:
140
Step-by-step explanation:
20+4(s)=
20+4(30)=
20+ 120=
140
Answer c
Step-by-step explanation:
they have to be equivalent
Answer:
26
Step-by-step explanation:
SORRY IF IM WRONG