8171 9 inches and different radius
Answer:
I think the answer might be 0.012
Step-by-step explanation:
You can get a vertical asymptote at x=1 using y = 1/(x-1)
You can generate a hole at x=3 by multiplying by (x - 3/(x - 3) which is undefined at x=3 but otherwise equals 1
You can move the horizontal asymptote up to y=2 by adding 2
y = (x - 3)/((x - 1)(x - 3)) + 2
Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r = 
= 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
=3.14 * 0.000976563
= 0.003066406
= 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!
Given:
15% of its height each day
27 inches on day 10.
How tall was it yesterday?
27 represents 115% of the height yesterday. So we divided 27 by 115% to get yesterdays height.
27 ÷ 115% = 23.48 inches.
The plant was 23.48 inches tall yesterday.
To check:
23.48 x 15% = 3.52 inches
23.48 + 3.52 = 27 inches
