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Maru [420]
2 years ago
11

( X ) -3, 0, 3

Mathematics
1 answer:
xxTIMURxx [149]2 years ago
4 0

Answer:

C

Step-by-step explanation:

Easy man ..............

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Help NOW PLEASE
-BARSIC- [3]

Answer

(3x-3)

Step-by-step explanation:

4 0
3 years ago
Perform the indicated operation g(x)=-x-3 h(x) = x 2+X Find (goh) (x)​
Klio2033 [76]

Answer:

(g\circ h)(x)=-x^2-x-3

Step-by-step explanation:

So we have the two functions:

g(x)=-x-3\text{ and } h(x)=x^2+x

And we want to find:

(g\circ h)(x)

This is the same thing as:

=g(h(x))

So, substitute h(x) into g(x):

g(x)=-x-3\\g(h(x))=-(x^2+x)-3

Distribute the negative:

g(h(x))=-x^2-x-3

And we're done!

So:

(g\circ h)(x)=-x^2-x-3

6 0
3 years ago
Read 2 more answers
Please help me thank you
KengaRu [80]

Answer:

false buddy that is the answer

6 0
2 years ago
Need Help (: Help me pls Brainly dont take
joja [24]
$171.45

135 x 0.27 + 135
8 0
3 years ago
Please sketch graph of the function f(x) = |x+2|.
Burka [1]

Answer:

The absolute value can be graphed using the points around the vertex (-2, 0), (-4, 2), (-3, 1), (-1, 1), (0, 2).

Step-by-step explanation:

The find the x coordinate of the vertex, set the inside of the absolute value x + 2 equal to 0. In this case, x + 2 = 0.

x + 2 = 0

Subtract 2 from both sides of the equation.

x = -2

Replace the variable x with -2 in the expression.

y = |(-2) + 2|

The absolute value vertex is (-2, 0).

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

For each x value, there is on y value. Select few z values from the domain. It would be more useful to select the values so that they are around the x value of the absolute value vertex.

Substitute the x value -4 into f(x) = |x+2|. In this case, the point is (-4,2).

y=2

Substitute the x value -3 into f(x) = |x+2|. In this case, the point is (-3,1).

y=1

Substitute the x value 0 into f(x) = |x+2|. In this case, the point is (0,2).

y=2

You can find the graph in the attachment.

6 0
3 years ago
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