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3 years ago

The diagram below represents a horizontal force of 20 newtons applied to a 5.0 kilogram box to push it and

Physics

1 answer:

andreev551 [17]3 years ago

8 0

Answer:

20 N

Explanation:

There are two forces acting on the box:

- The force of push, F, forward, of magnitude F = 20 N

- The force of friction, $F_f$ , backward

So, the equation of motion for the box is

$F-F_f = ma$

where

m = 5.0 kg is the mass of the box

a is its acceleration

The box is sliding at constant velocity: this means that its acceleration is zero

a = 0

So, the equation becomes

$F-F_f = 0$

Therefore, we can find the magnitude of the force of friction:

$F_f = F = 20 N$

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Answer:

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