Question

The diagram below represents a horizontal force of 20 newtons applied to a 5.0 kilogram box to push it and

Answer 1

Answer:

20 N

Explanation:

There are two forces acting on the box:

- The force of push, F, forward, of magnitude F = 20 N

- The force of friction, $F_f$, backward

So, the equation of motion for the box is

$F-F_f = ma$

where

m = 5.0 kg is the mass of the box

a is its acceleration

The box is sliding at constant velocity: this means that its acceleration is zero

a = 0

So, the equation becomes

$F-F_f = 0$

Therefore, we can find the magnitude of the force of friction:

$F_f = F = 20 N$