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3 years ago

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A hedgehog runs 500 meters in 10 minutes, then 300 meters in 8 minutes and finally 100 meters in 6 minutes. What is the hedgehog

's average speed in meters per minutes?

1 answer:

Marina86 [1]3 years ago

5 0

200 meters per minutes

500 meters -300 meters= 200 meters

300 meters -100 meters =200 meters

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Whose view was that the Cosmos was based on the belief that every occurrence in the physical universe had logos behind it and th

Fiesta28 [93]

Answer:

Aristotle

Explanation:

Aristotelian theory of the Universe

For two millennia, the philosophical tradition considered that the universe was eternal and did not change. The wise Aristotle said so, with total clarity and his ideas dominated Western thought for more than two thousand years.

This distinguished philosopher believed that the stars are made of an imperishable matter and that the landscapes of the sky are immutable.

From the time of Aristotle until the beginning of the twentieth century, the idea that the universe was static, that the cosmos had been eternally equal, was admitted.

In those years, the origin of the universe was not really considered in a scientific way, since it was based on the basis that the gods had created everything that exists, at the time they wanted it, according to their omnimous power.

So that all the efforts of the wise men of the time focused on discovering the existing organization in the universe created by the gods.

According to Aristotle and the thinkers of the fourth century B.C. what is below the Moon is a changing world, what is beyond the Moon is an immutable world.

6 0

3 years ago

In air, the 57 GHz radio wave has a shorter<br> wavelength compared to the 64 GHz radio wave.

dalvyx [7]

Answer:

False

Explanation:

Higher frequency signals have shorter wavelengths. Hence, the 64 GHz signal will have a shorter wavelength than the 57 GHz signal.

Frequency and wavelength are inversely proportional meaning as frequency increases wavelength decreases and as frequency decreases wavelength increases.

Cheers.

6 0

3 years ago

A mass on a spring oscillates with a period T. Part A If both the mass and the force constant of the spring are doubled, the new

garik1379 [7]

Answer:

The new time period will be T.

Explanation:

The time period in terms of spring constant and mass is given by :

$T=2\pi\sqrt{\dfrac{m}{k}}$

If mass and force constant is doubled, m' = 2m and k' = 2k

New time period is given by :

$T'=2\pi\sqrt{\dfrac{m'}{k'}}$

$T'=2\pi\sqrt{\dfrac{2m}{2k}}$

$T'=2\pi\sqrt{\dfrac{m}{k}}$

$T'=T$

So, the new period will remains the same. Hence, the correct option is (C).

4 0

3 years ago

The fastest measured pitched baseball left the pitcher's hand at a speed of 42.0 m/s. If the pitcher was in contact with the bal

I am Lyosha [343]

Answer:

The acceleration and time are 588 m/s² and 0.071 sec respectively.

Explanation:

Given that,

Speed = 42.0 m/s

Distance = 1.50 m

(a). We need to calculate the acceleration

Using equation of motion

$v^2=u^2+2as$

$a=\dfrac{v^2-u^2}{2s}$

Put the value in the equation

$a=\dfrac{42.0^2-0}{2\times1.50}$

$a=588\ m/s^2$

(b). We need to calculate the time

Using equation of motion

$v = u+at$

$t=\dfrac{v-u}{a}$

$t=\dfrac{42.0-0}{588}$

$t=0.071\ sec$

Hence, The acceleration and time are 588 m/s² and 0.071 sec respectively.

8 0

3 years ago

Charge q1 = +2.00 μC is at -0.500 m along the x axis. Charge q2 = -2.00 μC is at 0.500 m along the x axis. Charge q3 = 2.00 μC i

Kobotan [32]

The magnitude of <em>electrical</em> force on charge $q_{3}$ due to the others is 0.102 newtons.

<h3>How to calculate the electrical force experimented on a particle</h3>

The vector <em>position</em> of each particle respect to origin are described below:

$\vec r_{1} = (-0.500, 0)\,[m]$

$\vec r_{2} = (+0.500, 0)\,[m]$

$\vec r_{3} = (0, +0.500)\,[m]$

Then, distances of the former two particles particles respect to the latter one are found now:

$\vec r_{13} = (+0.500, +0.500)\,[m]$

$r_{13} = \sqrt{\vec r_{13}\,\bullet\,\vec r_{13}} = \sqrt{(0.500\,m)^{2}+(0.500\,m)^{2}}$

$r_{13} =\frac{\sqrt{2}}{2}\,m$

$\vec r_{23} = (-0.500, +0.500)\,[m]$

$r_{23} = \sqrt{\vec r_{23}\,\bullet \,\vec r_{23}} = \sqrt{(-0.500\,m)^{2}+(0.500\,m)^{2}}$

$r_{23} =\frac{\sqrt{2}}{2}\,m$

The resultant force is found by Coulomb's law and principle of superposition:

$\vec R = \vec F_{13}+\vec F_{23}$ (1)

Please notice that particles with charges of <em>same</em> sign attract each other and particles with charges of <em>opposite</em> sign repeal each other.

$\vec R = \frac{k\cdot q_{1}\cdot q_{3}}{r_{13}^{2}}\cdot \vec u_{13} +\frac{k\cdot q_{2}\cdot q_{3}}{r_{23}^{2}}\cdot \vec u_{23}$ (2)

Where:

$k$ - Electrostatic constant, in newton-square meters per square Coulomb.
$q_{1}$ , $q_{2}$ , $q_{3}$ - Electric charges, in Coulombs.
$r_{13}$ , $r_{23}$ - Distances between particles, in meters.
$\vec u_{13}$ , $\vec u_{23}$ - Unit vectors, no unit.

If we know that $k = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}$ , $q_{1} = 2\times 10^{-6}\,C$ , $q_{2} = 2\times 10^{-6}\,C$ , $q_{3} = 2\times 10^{-6}\,C$ , $r_{13} =\frac{\sqrt{2}}{2}\,m$ , $r_{23} =\frac{\sqrt{2}}{2}\,m$ , $\vec u_{13} = \left(-\frac{\sqrt{2}}{2}, - \frac{\sqrt{2}}{2} \right)$ and $\vec u_{23} = \left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right)$ , then the vector force on charge $q_{3}$ is:

$\vec R = \frac{\left(8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} \right)\cdot (2\times 10^{-6}\,C)\cdot (2\times 10^{-6}\,C)}{\left(\frac{\sqrt{2}}{2}\,m \right)^{2}} \cdot \left(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right) + \frac{\left(8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} \right)\cdot (2\times 10^{-6}\,C)\cdot (2\times 10^{-6}\,C)}{\left(\frac{\sqrt{2}}{2}\,m \right)^{2}} \cdot \left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right)$

$\vec R = 0.072\cdot \left(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right) + 0.072\cdot \left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right)\,[N]$

$\vec R = 0.072\cdot \left(0, -\sqrt{2}\right)\,[N]$

And the magnitude of the <em>electrical</em> force on charge $q_{3}$ ( $R$ ), in newtons, due to the others is found by Pythagorean theorem:

$R = 0.102\,N$

The magnitude of <em>electrical</em> force on charge $q_{3}$ due to the others is 0.102 newtons. $\blacksquare$

To learn more on Coulomb's law, we kindly invite to check this verified question: brainly.com/question/506926

8 0

2 years ago