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3 years ago

Write a set of directions that tells an operating system’s dispatcher what to do when a process time slice is over.

Computers and Technology

2 answers:

lorasvet [3.4K]3 years ago

7 0

Answer and explanation:

Hold on to be executed by the interrupt handler. Enable updating of the process table to the scheduler. Choose the process that forms the process table with the highest priority, restart the time and allow the process selected to start its time slice.

tatyana61 [14]3 years ago

6 0

<span> Directions that tells an operating system's dispatcher what to do when a process's time slice is over.Wait for the interrupt handler to be execute. Allow the scheduler to update the process table. Select the process form the process table that has the highest priority, restart the time, and allow the selected process to begin its time slice. Directions that tells an operating system's dispatcher what to do when a process's time slice is over. Signal an interrupt, save the current position, execute the current position, execute the interrupt handler, and switch to the next process until the process or processes is complete. If a process executes an I/O request, the time slice of that process will be terminated because it would waste the remaining time waiting for the controller to perform the request. A situation in a time-sharing system in which a process does not consume the entire time slice allotted to it. Client/server model Defines the basic roles played by the processes as being that of either a client, which makes requests of other processes Components of the email address </span>

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Make a program that (i) asks the user for a temperature in Fahrenheit degrees and reads the number; (ii) computes the correspond

Lerok [7]

<h2>Answer:</h2><h2></h2>

//import the Scanner class to allow for user's input

import java.util.Scanner;

//Create a class declaration with appropriate name

public class FahrenheitToCelsius {

//Begin the main method where execution starts from

public static void main(String[] args) {

//Create an object of the Scanner class to allow reading from standard

// input

Scanner input = new Scanner(System.in);

//Prompt the user to enter the temperature

System.out.println("Enter a temperature in Fahrenheit degrees");

//Read the number and store in a variable of type double

double fahrenheit = input.nextDouble();

//Convert the temperature to Celsius

double celsius = (fahrenheit - 32) * (5 / 9.0);

//Print out the result

System.out.println("The temperature in Celsius is " + celsius);

} //End of main method

} //End of class declaration

==============================================================

<h2>Sample Output 1:</h2><h2 />

>> Enter a temperature in Fahrenheit degrees

>> The temperature in Celsius is 0.0

==============================================================

<h2>Sample Output 2:</h2><h2 />

>> Enter a temperature in Fahrenheit degrees

>> The temperature in Celsius is 25.555555555555557

===============================================================

<h2>Explanation:</h2>

The code has been written in Java and it contains comments explaining every segment of the code. Please go through the comments.

The actual lines of code are written in bold face to separate them from the comments.

Sample outputs have also been given to show how the result of the program looks like.

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Answer: Hello your required question is wrong as it does not tally with the data provided , attached below is the complete question

answer:

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Explanation:

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Lady_Fox [76]

Answer:

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2 years ago

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; This program replaces the value in R0 with its absolute value. ; ; It does NOT modify any other registers! ; .ORIG x0200 START

olasank [31]

Using the knowledge in computational language in LC-3 Assembly it is possible to write a code that replaces the value in R0 with its absolute value

<h3>Writting the code </h3>

.ORIG x0200

START

AND R0, R0, #0 ; copy R0 to itself to set the condition codes based on R0;

; i.e performing addition operation with Zero option to set the flags

BRzp DONE ; if R0 is NON-NEGATIVE, skip the negation (already correct);

; Branch to DONE if number is poistive

NOT R0, R0 ; R0 is negative, so negate it i.e taking 2's complement

ADD R0, R0, #1 ; R0 = -R0 is performed successfully

DONE BR START

.END

See more about LC-3 Assembly at brainly.com/question/12978370