2 4/5 times 2 times 3/5
1 answer:
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Answer:
a) 0.4164
Step-by-step explanation:
Mean lifespan (μ) = 18.8 days
Standard deviation (σ) = 2 days
For any given lifespan 'X', the z-score is:
For X=12.04 days:
A z-score of -3.38 falls in the 0.036-th percentile of a normal distribution.
For X=18.38 days:
A z-score of -3.38 falls in the 41.68th percentile of a normal distribution.
The probability that a butterfly lives between 12.04 and 18.38 days is