Answer:
The area of the shaded figure is:
Step-by-step explanation:
To obtain the area of the shaded figure, first, you must calculate this as a rectangle, with the measurements: wide (4 units), and long (6 units):
- Area of a rectangle = long * wide
- Area of a rectangle = 6 * 4
- Area of a rectangle = 24 units^2
How the figure isn't a rectangle, you must subtract the triangle on the top, so, now we calculate the area of that triangle with measurements: wide (4 units), and height (2 units):
- Area of a triangle =

- Area of a triangle =

- Area of a triangle =

- Area of a triangle = 4 units^2
In the end, you subtract the area of the triangle to the area of the rectangle, to obtain the area of the shaded figure:
- Area of the shaded figure = Area of the rectangle - Area of the triangle
- Area of the shaded figure = 24 units^2 - 4 units^2
- <u>Area of the shaded figure = 20 units^2</u>
I use the name "units" because the exercise doesn't say if they are feet, inches, or another, but you can replace this in case you need it.
7:14 or simplified 1:2 (use simplified)
Find total amount of fruit by adding
4+7+3=14
7 pears to 14 total fruits in ratio form is 7:14 which simplifies to 1:2
Answer:
180
Step-by-step explanation:
for two angles to be supplementary, their sum must be equal to 180°
Answer:
See below
Step-by-step explanation:
![9.( {m}^{3} {n}^{5} )^{ \frac{1}{4} } \\ = m^{\frac{3}{4}}n^{\frac{5}{4}}\\ \\ 10. \sqrt[5]{ \sqrt[4]{x} } \\ = \sqrt[5]{ {x}^{ \frac{1}{4} } } \\ = {( {x}^{ \frac{1}{4} } )}^{ \frac{1}{5} } \\ = {x}^{ \frac{1}{4} \times \frac{1}{5} } \\ = {x}^{ \frac{1}{20} } \\ \\ \sqrt[5]{ \sqrt[3]{ {a}^{2} } } \\ = \sqrt[5]{ {a}^{ \frac{2}{3} } } \\ = {( {a}^{ \frac{2}{3} } )}^{ \frac{1}{5} } \\ = {a}^{ \frac{2}{3} \times \frac{1}{5} } \\ = {a}^{ \frac{2}{15} }](https://tex.z-dn.net/?f=9.%28%20%7Bm%7D%5E%7B3%7D%20%20%7Bn%7D%5E%7B5%7D%20%29%5E%7B%20%5Cfrac%7B1%7D%7B4%7D%20%7D%20%20%20%5C%5C%20%20%20%3D%20%20m%5E%7B%5Cfrac%7B3%7D%7B4%7D%7Dn%5E%7B%5Cfrac%7B5%7D%7B4%7D%7D%5C%5C%20%20%5C%5C%2010.%20%5Csqrt%5B5%5D%7B%20%5Csqrt%5B4%5D%7Bx%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%5B5%5D%7B%20%7Bx%7D%5E%7B%20%5Cfrac%7B1%7D%7B4%7D%20%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%7B%28%20%7Bx%7D%5E%7B%20%5Cfrac%7B1%7D%7B4%7D%20%7D%20%29%7D%5E%7B%20%5Cfrac%7B1%7D%7B5%7D%20%7D%20%20%5C%5C%20%20%20%3D%20%20%7Bx%7D%5E%7B%20%5Cfrac%7B1%7D%7B4%7D%20%20%5Ctimes%20%20%5Cfrac%7B1%7D%7B5%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%7Bx%7D%5E%7B%20%5Cfrac%7B1%7D%7B20%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%5Csqrt%5B5%5D%7B%20%5Csqrt%5B3%5D%7B%20%7Ba%7D%5E%7B2%7D%20%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%5B5%5D%7B%20%7Ba%7D%5E%7B%20%5Cfrac%7B2%7D%7B3%7D%20%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%7B%28%20%7Ba%7D%5E%7B%20%5Cfrac%7B2%7D%7B3%7D%20%7D%20%29%7D%5E%7B%20%5Cfrac%7B1%7D%7B5%7D%20%7D%20%20%5C%5C%20%20%20%3D%20%20%7Ba%7D%5E%7B%20%5Cfrac%7B2%7D%7B3%7D%20%20%5Ctimes%20%20%5Cfrac%7B1%7D%7B5%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%7Ba%7D%5E%7B%20%5Cfrac%7B2%7D%7B15%7D%20%7D%20%20)
Answer:
C
Step-by-step explanation:
The pre-image of a reduction is always bigger. Reduction means to "get smaller," so the pre-image needs to be bigger than the ending image.