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Leokris [45]
3 years ago
14

Joe walks on a treadmill at a constant rate. The equation below describes the relationship between t, the time he walks in hours

, and d, the distance he walks in miles. Can someone help me with the answer...I’m not sure if it’s B or c....I know it’s not A and D.
Mathematics
1 answer:
tigry1 [53]3 years ago
4 0

Answer:

3r1ifguqeigdvcig3p1iyrg f837grygqdowgvy

Step-by-step explanation:

qwriug13uorgv[13rhh1worugv

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Linear or nonlinear​
Wittaler [7]

Answer:

Linear

Step-by-step explanation:

It increases by a steady rate, so it is linear.

5 0
3 years ago
Mrs. Carlson wrote the following question for her class: "Ricardo's basketball team is selling raffle tickets, Each ticket costs
IceJOKER [234]

Answer:

michelle, kaley, and Rebecca.

Step-by-step explanation:

They have sold 100 tickets so far ($75), they need to sell 380 ($285) tickets in total and need to sell 280 more tickets.

Michelle was wrong because she should have divided 210 (how much more money they need to sell on tickets) into .75 (which is how much each ticket costs).

Kaley was wrong because she should have also divided 210 into .75 like Michelle.

Rebecca should have also divided 210 into .75.

Eva was the only correct one.

7 0
3 years ago
Which property do i use to solve x-10=15
Stells [14]
Add both sides by 10

x=25
3 0
3 years ago
What does the equal
sergejj [24]
Plug it in your y= screen of your graphing calculator and hit 2nd and then graph. it will give u a table of values
7 0
3 years ago
et f(x) = x + |2x − 3|. Find all solutions to the equation f(x) = 12. (Enter your answers as a comma-separated list. If an answe
Alinara [238K]

Answer:

1. {5,-9}

2.{4}

3.{9/2}

Step-by-step explanation:

The equation f(x)=x+\lvert 2x-3 \rvert=12 can be solved as follows:

x+\lvert 2x-3 \rvert =12\,\,\,\text{(given equation)}

\lvert 2x-3 \rvert =12-x

2x-3=12-x\,\,\text{or}\,\,2x-3=-(12-x)

3x=15\,\,\text{or}\,\,\x=-9

Then, the solutions of the equation are x=5, x=-9.

Now, if g(x)=5x-3+\lvert x+4\rvert, we can solve the equation g(a)=4a+9 as follows:

5a-3+\lvert a+4 \rvert =4a+9

\lvert a+4\rvert =4a+9-5a+3

a+4 =-a+12\,\,\text{or}\,\,a+4=-(-a+12)

2a=8\,\,\text{or}\,\,4=12

So, the unique solution of this last equation is a=4

The last equation is h(x-1)=x-3, where h(x)=\lvert x \rvert -2x+5.. To solve this equation we can proceed as follows:

h(x-1)=x-3

\lvert x-1\rvert -2(x-1)+5=x-3

\lvert x-1 \rvert -2x+2+5=x-3

\lvert x-1\rvert =3x-10

x-1=3x-10\,\,\text{or}\,\,x-1=-(3x-10)

-2x=-9\,\,\text{or}\,\,4x=11

x=9/2\,\,\text{or}\,\,x=11/4

But, x=11/4 is not a solution of this equation. So the unique solution is x=9/2.

8 0
2 years ago
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