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3 years ago

Identify the radius of the circle whose equation is x^2 + y^2 = 36.

Mathematics

1 answer:

pantera1 [17]3 years ago

3 0

Answer:

radius = 6

Step-by-step explanation:

The equation of a circle centred at the origin is

x² + y² = r² ←r is the radius

x² + y² = 36 ← is in this form

with r² = 36 ⇒ r = $\sqrt{36}$ = 6

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Answer:

Given that:

$L(t) = 52\sin(\frac{2 \pi t}{365})+728$

where

L(t) represents the length of each day(in minutes) and t represents the number of days.

Substitute the value of L(t) = 750 minutes we get;

$750= 52\sin(\frac{2 \pi t}{365})+728$

Subtract 728 from both sides we get;

$22= 52\sin(\frac{2 \pi t}{365})$

Divide both sides by 52 we get;

$0.42307692352= \sin(\frac{2 \pi t}{365})$

$\frac{2 \pi t}{365} = \sin^{-1} (0.42307692352)$

Simplify:

$\frac{2 \pi t}{365} =0.43683845$

$t = \frac{365 \times 0.43683854}{2 \times \pi} = \frac{365 \times 0.43683854}{2 \times 3.14}$

Simplify:

$t \approx 25$ days

Therefore, the first day after the spring equinox that the day length is 750 minutes, is 25 days

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