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Alexxandr [17]
2 years ago
5

theirs a picture up their how do I know where I put the what numbers in each angle so like how do I know if 68 degrees goes in a

ngle 1 or 3 ect please help

Mathematics
1 answer:
ArbitrLikvidat [17]2 years ago
4 0
If a line intersects two parallel lines, the obtuse angles will be congruent and so will acute angles.

it means that angles 2,4,6,8 are congruent and they all measure 68 (given)

and angles 1,3,5,7 are congruent and they all measure 112 degrees (180-68=112)




good luck
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3 years ago
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For the function f(x) = 1/4e^-x + e^x, prove that the arc length on any interval has the same value as the area under the curve.
faltersainse [42]

Take an arbitrary interval [<em>a</em>, <em>b</em>], where <em>a</em> < <em>b</em>.

Compute the arc length <em>L</em> of <em>y</em> = <em>f(x) </em>over [<em>a</em>, <em>b</em>] :

L=\displaystyle\int_a^b\sqrt{1+\left(f'(x)\right)^2}\,\mathrm dx

Now comptue the area <em>A</em> under the curve <em>y</em> = <em>f(x)</em> over [<em>a</em>, <em>b</em>] :

A=\displaystyle\int_a^bf(x)\,\mathrm dx

We have

<em>f</em> (<em>x</em>) = 1/4 <em>e</em> ⁻ˣ + <em>e </em>ˣ   →   <em>f ' </em>(<em>x</em>) = -1/4 <em>e</em> ⁻ˣ + <em>e </em>ˣ

Then

√(1 + (<em>f '</em> (<em>x</em>))²) = √(1 + (-1/4 <em>e</em> ⁻ˣ + <em>e </em>ˣ)²)

… = √(1 + 1/16 <em>e</em> ⁻²ˣ - 1/2 + <em>e </em>²ˣ)

… = √(1/16 <em>e</em> ⁻²ˣ + 1/2 + <em>e </em>²ˣ)

… = 1/4 √(<em>e</em> ⁻²ˣ + 8 + 16<em>e </em>²ˣ)

… = 1/4 √((<em>e</em> ⁻ˣ + 4 <em>e</em> ˣ)²)

… = 1/4 (<em>e</em> ⁻ˣ + 4 <em>e</em> ˣ)

… = 1/4 <em>e</em> ⁻ˣ + <em>e</em> ˣ

… = <em>f</em> (<em>x</em>)

so both <em>A</em> = <em>L</em> for any choice of interval [<em>a</em>, <em>b</em>].

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3 years ago
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