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Black_prince [1.1K]
3 years ago
9

Two distinct points are_

Mathematics
1 answer:
weeeeeb [17]3 years ago
5 0

A) never

Two distinct points are _never_ connected by two distinct lines.

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The following data represent weights (pounds) of a random sample of professional football players on the following teams. X1 = w
alexandr1967 [171]

I don't have an idea of what the answer is to be honest.

8 0
2 years ago
Please help me simplify these expressions
Archy [21]

Answer:

Step-by-step explanation:

If base of variable is same, add the powers

1) x² * x * x³ * x⁵ = x²⁺¹⁺³⁺⁵ = x¹¹

2) -2n² * -n⁴ * 5n³ = (-2* -1*  5 ) *n²⁺⁴⁺³ = 10n⁹

3)-3x⁴ * 2x⁵ * - x = (-3 * 2 * -1)* x⁵⁺⁴⁺¹ = 6x¹⁰

5 0
3 years ago
Read 2 more answers
Solve<br> 2(x+3)=x-4<br><br> im not sure what to do with this question
vovangra [49]

Answer:

x = -10

Step-by-step explanation:

2(x + 3) = x - 4

2x + 6 = x - 4

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3 0
3 years ago
What is the x intercept of -6x-3y=18?
damaskus [11]
<span>-6x-3y=18
Substitute 0 for y
-6x-3(0)=18
Multply -3 by 0
-6x=18
Divide both sides by -6 so that the only thing on the left side is the variable x.
Final Answer: x= -3</span>
4 0
3 years ago
What is the equation in point slope form of the line that is parallel to the given line and passes through the point (4,1)?
vovikov84 [41]

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

y-1=\stackrel{\stackrel{m}{\downarrow }}{2}(x-4)\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}

so we're really looking for the equation of a line with a slope of 2 and that it passes through (4 , 1)

(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\hspace{10em} \stackrel{slope}{m} ~=~ 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{2}(x-\stackrel{x_1}{4})

kinda twins.

8 0
1 year ago
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