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3 years ago

Two distinct points are_

Mathematics

1 answer:

weeeeeb [17]3 years ago

5 0

A) never

Two distinct points are _never_ connected by two distinct lines.

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Solve for x and y pls

Paraphin [41]

X is a 90 degree angle so x equals half of 90 which is 45
X= 45
Since x is 45 the other angle on the other side is 45
Every triangle equals 180 so you take 45+45 to get 90 and subtract that from 180 and get 90
Y= 90
hope this helped ask questions

8 0

3 years ago

1 spinner is divided into 5 equal sections numbered 1 to 5 a second spinner is divided into 7 equal section number 6 to 12 how m

Tcecarenko [31]

Answer:

Step-by-step explanation:

3 0

3 years ago

Simplify the given expression below: (−3 + 2i) ⋅ (2 + i)

alina1380 [7]

The answer is : -8 + i

6 0

3 years ago

Let Y1 < Y2 < Y3 < Y4 < Y5 be the order statistics of five independent observations from an exponential distribution

Katena32 [7]

Answer:

a) $10[1-e^{-y/3} ] ^{2} e^{-y}$

b) ≈ 0.76

Step-by-step explanation:

Given that : Y1 < Y2 < Y3 < Y4 < Y5 are the order statistics of five independent observations

mean of θ = 3

<u>a) Determine the P.d.f of the sample median </u>

P.d.f of sample median ( y3 ) = $10[1-e^{-y/3} ] ^{2} e^{-y}$

attached below is the detailed solution

<u>b) determine the probability that Y4 is < 5 </u>

p( Y4 < 5 ) = G4( 5 )

= 0.7599 ≈ 0.76

attached below is the detailed solutions

8 0

3 years ago

1 ) During his morning commute to work in rush hour traffic, Justin's average speed was 30 mi/h. During his afternoon commute ba

Hitman42 [59]

Answer:45 mi/h

Step-by-step explanation:

Recall: Speed = distance / time

Let the time taken for the morning journey be $t_{1}$ and the time taken for the afternoon journey be $t_{1}$ ,and the distance covered be d

that means for the first journey,

30 = $\frac{d}{t_{1}}$

d = 30 $t_{1}$

Also for the afternoon journey,

d = 60 $t_{2}$

Equating the two , since the same distance is being covered , we have

30 $t_{1}$ = 60 $t_{2}$

that is

$t_{1}$ = $\frac{60t_{2}}{30}$

$t_{1}$ = 2 $t_{2}$

Also ,

total distance covered = 30 $t_{1}$ + 60 $t_{2}$

Average speed = total distance / total time

= 30 $t_{1}$ + 60 $t_{2}$ / $t_{1}$ + $t_{2}$

Recall that $t_{1}$ = 2 $t_{2}$ , substitute this into the formula for average speed , then we have

Average speed = 30(2 $t_{2}$ ) +60 $t_{2}$ / 3 $t_{2}$

Average speed = 120 $t_{2}$ / 3 $t_{2}$

Therefore :

Average speed = 40 mi/hr

4 0

3 years ago