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Schach [20]
3 years ago
8

Find three consecutive integers such that three times the first added to the last is 22

Mathematics
1 answer:
Finger [1]3 years ago
4 0
Consetive integers are 1 apart
they are
x,x+1,x+2

3 times the first added to the last is 22
3x+x+2=22
combine like terms
4x+2=22
minus 2 both sides
4x=20
divide both sides by 4
x=5
x+1=6
x+2=7

the numbers are 5,6,7
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121 over 121 all the names that apply to each number
spayn [35]
121 over 121 is a whole number of 1

6 0
2 years ago
The other answers I already did I just need the division answers​
Oxana [17]

Answer:

6÷41 equals 0.14634146341

6÷21 equals 0.28571428571

6÷43 equals 0.13953488372

6÷37 equals 0.16216216216

6÷20 equals 0.3

Step-by-step explanation:

Hope this helps

5 0
2 years ago
The expression 21 - (2x + 3)2 + 4 (1 - 1) + z3 can be simplified into the form
mr Goodwill [35]

Answer:

A=z

B=-2

C=0

D=30

Step-by-step explanation:

First lets simply the equation

21 - (2x +3)2 + 4(1-1) + z^3

21 - (2x^2 + 9) + 4(0) + z ^3

21 - 2x^2 + 9 + z^3

- 2x^2 + z ^3 + 30

This means that:

A=z

B=-2

C=0

D=30

5 0
3 years ago
Solve the inequality<br> 4b−4≤−20
devlian [24]

Answer:

b ≤ -4

Step-by-step explanation:

4b−4≤−20

4b - 4 + 4 ≤ - 20 + 4

4b ≤ -16

Divide both sides by 4

b ≤ -4

8 0
2 years ago
1 1/10 divided by 1 4/7
Sergio039 [100]
The answer is 7/10. Do you need help with any other problems?
7 0
3 years ago
Read 2 more answers
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