The correct answer is D <span>9.87 times 10 to the 4</span>
It's 3.2 units
hope it's helps
Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
Using the x and y intercepts from the graph to find the slope of the line:
slope = (0 - 2) / (4 - 0)
slope = -1/2
Using the point-slope form:
y - 0 = -1/2 (x - 4)
-2y = x - 4
4 = x + 2y
Coefficient of x is 1 and coefficient of y is 2.
2x + 3(6) = 36
2x + 18 = 36
2x = 18
x = 9
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