Train A:
Distance (s) = 420 miles
Time (t) = 3 hours
Speed (v) = distance ÷ time = 420 ÷ 3 = 140 miles/hour
Train B:
Distance (s) = 420 miles
Time (t) = 2.25 hours
Speed (v) = distance ÷ time = 420 ÷ 2.25 = 186.7 miles/hour
Answer:
HI TO YOU HAVE A GOOD DAY AND NICE DAY
Answer:
Step-by-step explanation:
We observe that the difference of terms is 4, 7 and 15 and next level difference is 4. It means the sequence is quadratic.
<u>We can compare this with simple quadratic sequence </u>
<u>and find out that doubling each term gives us </u>
This is close to our sequence, write the terms as follows to find exact rule
<u>The first term: </u>
- a₁ = 4 = 2*1² + 2 = 2*1² + 1 + 1
<u>The second term</u>
- a₂ = 11 = 2*2² + 3 = 2*2² + 2 + 1
<u>The third term:</u>
- a₃ = 22 = 2*3² + 4 = 2*3² + 3 + 1
<u>The fourth term:</u>
- a₄ = 37 = 2*4² + 5 = 2*4² + 4 + 1
<u>The nth term as per observation above is:</u>
Answer:
4x-y+1=0
Step-by-step explanation:
here,given equation of a line id
4x-y-2=0.. eqn(i)
equation of any line parallel to line (i) is
4x-y+k=0...eqn(ii)
since, the line(ii) passes through (1,5)[replacing x=1 and y=5 in eqn(ii), we get]
4*1-5+k=0
or, 4-5+k=0
or,-1+k=0
•°•k=1
substituting the value of k=1 in eqn(ii),
4x-y+1=0 is the required equation of the line.
